Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function

Generalized resolvents of a minimal symmetric relation generated on the semi-axis by a formally selfadjoint di erential expression and a nonnegative operator function are described.

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Дата:2006
Автор: Bruk, V.M.
Формат: Стаття
Мова:English
Опубліковано: Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України 2006
Назва видання:Журнал математической физики, анализа, геометрии
Онлайн доступ:http://dspace.nbuv.gov.ua/handle/123456789/106676
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Цитувати:Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function / V.M. Bruk // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 4. — С. 372-387. — Бібліогр.: 11 назв. — англ.

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spelling irk-123456789-1066762016-10-03T03:02:12Z Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function Bruk, V.M. Generalized resolvents of a minimal symmetric relation generated on the semi-axis by a formally selfadjoint di erential expression and a nonnegative operator function are described. 2006 Article Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function / V.M. Bruk // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 4. — С. 372-387. — Бібліогр.: 11 назв. — англ. 1812-9471 http://dspace.nbuv.gov.ua/handle/123456789/106676 en Журнал математической физики, анализа, геометрии Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
collection DSpace DC
language English
description Generalized resolvents of a minimal symmetric relation generated on the semi-axis by a formally selfadjoint di erential expression and a nonnegative operator function are described.
format Article
author Bruk, V.M.
spellingShingle Bruk, V.M.
Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
Журнал математической физики, анализа, геометрии
author_facet Bruk, V.M.
author_sort Bruk, V.M.
title Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
title_short Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
title_full Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
title_fullStr Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
title_full_unstemmed Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function
title_sort generalized resolvents of symmetric relations generated on semi-axis by a differential expression and a nonnegative operator function
publisher Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України
publishDate 2006
url http://dspace.nbuv.gov.ua/handle/123456789/106676
citation_txt Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Differential Expression and a Nonnegative Operator Function / V.M. Bruk // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 4. — С. 372-387. — Бібліогр.: 11 назв. — англ.
series Журнал математической физики, анализа, геометрии
work_keys_str_mv AT brukvm generalizedresolventsofsymmetricrelationsgeneratedonsemiaxisbyadifferentialexpressionandanonnegativeoperatorfunction
first_indexed 2025-07-07T18:51:07Z
last_indexed 2025-07-07T18:51:07Z
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fulltext Journal of Mathematical Physics, Analysis, Geometry 2006, vol. 2, No. 4, pp. 372�387 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis by a Di�erential Expression and a Nonnegative Operator Function V.M. Bruk Saratov State Technical University 77 Politechnitseskaja Str., Saratov, 410054, Russia E-mail:bruk@san.ru Received July 10, 2005 Generalized resolvents of a minimal symmetric relation generated on the semi-axis by a formally selfadjoint di�erential expression and a nonnegative operator function are described. Key words: symmetric relation, generalized resolvent, characteristic ope- rator function, inductive limit, projective limit. Mathematics Subject Classi�cation 2000: 47A06, 47A10, 34B27. 1. Introduction In [1], A.V. Straus described the generalized resolvents of the symmetric ope- rator generated by a formally selfadjoint di�erential expression of even order in a scalar case. In [2] these results were used for the operator case. A di�erential expression with a nonnegative weight generates a linear relation. This relation is not an operator, in general. The generalized resolvents formulae for these relations are given in [3�5]. However, in these papers either the �nite-dimensional case [3, 5] or the in�nite-dimensional case [3, 4] under conditions that the kernel (the null space) of the maximal relation contained only solutions of the corres- ponding homogeneous equation was considered. In our paper a general situation is considered. We use projective and inductive limits of special spaces in the singular case to construct the spaces where a characteristic operator function acts. We consider the case of semi-axis instead of the general singular case only to simplify notations. The detailed bibliography is given in [1�5] and in the monograph [6]. c V.M. Bruk, 2006 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... 2. Notations and Auxiliary Formulae Let H be a separable Hilbert space with the scalar product (�; �) and the norm k�k; A(t) be an operator function strongly measurable on the interval [a;1); the values of A(t) are bounded operators in H such that for all x 2 H the scalar product (A(t)x; x) � 0 almost everywhere. Suppose the norm kA(t)k is integrable on every compact interval [a; �] � [a;1). We denote by l the di�erential expression of order r (r = 2n or r = 2n+ 1): l[y] = 8>>< >>: nP k=1 (�1)kf(pn�k(t)y (k))(k) � i[(qn�k(t)y (k))(k�1) + (qn�k(t)y (k�1))(k)]g+ pn(t)y; nP k=0 (�1)kfi[(qn�k(t)y (k))(k+1) + (qn�k(t)y (k+1))(k)] + (pn�k(t)y (k))(k)g: Coe�cients of l are bounded selfadjoint operators in H. The leading coe�cients, p0(t) in the case of r = 2n and q0(t) in the case of r = 2n+ 1, have the bounded inverse operator almost everywhere. The functions pn�k(t) are strongly di�eren- tiable k times and the functions qn�k(t) are strongly di�erentiable k times in the case r = 2n, and k+1 times in the case r = 2n+1. In general, we do not assume the coe�cients of the expression l to be smooth as we have just said. According to [7] we treat l as a quasidi�erential expression. Quasi-derivatives for the expression l are de�ned in [7]. Suppose the functions pj(t), qm(t) are strongly measurable, the function q0(t) in the case r = 2n+1 is strongly di�erentiable, and the norms of functions p�10 (t); p�10 (t)q0(t); q0(t)p �1 0 (t)q0(t); p1(t); : : : ; pn(t); q0(t); : : : ; qn�1(t) (in the case r = 2n ); q00(t); q1(t); : : : ; qn(t); p0(t); : : : ; pn(t) (in the case r = 2n+ 1) are integrable on every compact interval [a; �] � [a;1). We de�ne the scalar product hy1; y2i = 1Z a (A(t)y1(t); y2(t))dt; where yi(t) are H-valued functions continuous on [a;1), and 1R a A1=2(t)yi(t) 2 dt < 1, i = 1; 2. By identifying with zero the functions y such that hy; yi = 0 and making the completion, we obtain the Hilbert space. We denote this space Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 373 V.M. Bruk by B = L2(H;A(t); a;1). Let ~y be some element belonging to B, i.e., ~y is a corresponding class of functions. If y1; y2 2 ~y, then y1; y2 are identi�ed with respect to the norm generated by the scalar product h�; �i. By ~y we denote the class of functions containing y. Suppose y 2 ~y. Without loss of generality, further we will often say that y(t) belongs to B. Let (a0; b0) � [a;1) and B0 = L2(H;A(t); a0; b0). If ~y 2 B0, then extending y by zero to the whole interval [a;1) we can consider that ~y 2 B. If ~y 2 B, then restricting y to the interval (a0; b0) we can consider that ~y 2 B0 (it is not excepted that ~y 6= 0 in B and ~y = 0 in B0). Let G(t) be the set of elements x 2 H such that A(t)x = 0, and H(t) be the orthogonal complement of G(t) in H, H = H(t)�G(t), and A0(t) be the restric- tion of A(t) to H(t). Suppose H� (t), �1 < � <1, is the Hilbert scale of spaces [8, Ch. 2] generated by the operator A�10 (t). For the �xed t; operator A 1=2 0 (t) is a continuous one-to-one mapping of H(t) = H0(t) onto H1=2(t). We denote the adjoint operator of A 1=2 0 (t) by  1=2 0 (t). The operator  1=2 0 (t) is a continuous one-to-one mapping of H �1=2(t) onto H(t) and  1=2 0 (t) is an extension of A 1=2 0 (t). Let ~A0(t) = A 1=2 0 (t) 1=2 0 (t). The operator ~A0(t) is a continuous one-to-one map- ping of H �1=2(t) onto H1=2(t) and ~A0(t) is an extension of A0(t). We denote ~A(t) (respectively ~A1=2(t)) the operator de�ned on H �1=2 �G(t) such that ~A(t) ( ~A1=2(t)) is equal to ~A0(t) (respectively  1=2 0 (t)) on H �1=2(t) and ~A(t)( ~A1=2(t)) is equal to zero on G(t). The operator ~A(t) ( ~A1=2(t)) is an extension of A(t) (A1=2(t) respectively). In [3] it is proved that spaces H �1=2(t) are measurable with respect to pa- rameter t [9, Ch. 1] whenever we take functions of the form ~A�10 (t)A1=2(t)h(t) instead of measurable functions, where h(t) is a measurable H-valued function. The space B is a measurable sum of spaces H �1=2(t) and B consists of elements (i.e., classes of functions) with representatives of the form ~A�10 (t)A1=2(t)h(t), where h(t) 2 L2(H; a;1), i.e., 1R a kh(t)k2 dt < 1. If y1, y2 are representatives of the class of functions ~y 2 B, then ~A1=2(t)y1(t), ~A1=2(t)y2(t) are the same func- tions in the space L2(H; a;1). We denote this function by ~A1=2(t)~y. We de�ne minimal and maximal relations generated by the expression l and the function A(t) in the following way. Let D0 0 be the set of �nite on (a;1) func- tions y satisfying the following conditions: a) the quasi-derivatives y[0]; : : : ; y[r] of function y exist, they are absolutely continuous up to the order r � 1; b) l[y](t) 2 H1=2(t) almost everywhere; c) the function ~A�10 (t)l[y] belongs to B. To each class of functions identi�ed in B with y 2 D0 0 we assign the class of functions identi�ed in B with ~A�10 (t)l[y]. This correspondence L00 may not be an operator as it may happen that some function y is identi�ed with zero in B and ~A�10 (t)l[y] 374 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... is not equal to zero. So, we get a linear relation L00 in the space B. The closure of L00 we denote by L0. The relation L0 is called as a minimal one. Let L�0 be the relation adjoint of L0. L � 0 is called the maximal relation. Terminology concerning linear relations can be found in the monographs [6, 8]. Further the following notations are used: R as a range of values; f�; �g as an ordered pair. We consider the di�erential equation l[y] = �A(t)y, where � is a complex number. Let Wj(t; �) be the operator solution of this equation satisfying the initial conditions: W [k�1] j (a; �) = ÆjkE (E is the identity operator, Æjk is the Kronecker symbol, j; k = 1; : : : ; r). By W (t; �) we denote the one-row operator matrix (W1(t; �); : : : ;Wr(t; �)). The operator W (t; �) maps continuously Hr into H for �xed t, �. The adjoint operator W �(t; �) maps continuously H into Hr. If l[y] exists for the function y, then we denote ŷ = (y; y[1]; : : : ; y[r�1]) (we treat ŷ as a one-columned matrix). Let z = (z1; : : : ; zm) be some system of functions such that l[zj ] exists for each j. By ẑ we denote the matrix (ẑ1; : : : ; ẑm). The analogous notations are used for the operator functions. We consider the operator matrices of orders 2n and 2n+1 for the expression l in cases r = 2n and r = 2n+ 1 respectively: J2n(t) = 0 BBBBBB@ �E ::: �E E ::: E 1 CCCCCCA ; J2n+1(t) = 0 BBBBBBBB@ �E ::: �E 2iq�10 (t) E ::: E 1 CCCCCCCCA ; where all the elements, that are not indicated, are equal to zero. (In matrix J2n+1(t) the element 2iq�10 (t) stands on the intersection of the row n+1 and the column n+1.) Suppose the expression l is de�ned for the functions y, z, then, in these notations, Lagrange's formula has the following form: �Z � (l[y]; z)dt � �Z � (y; l[z])dt = (Jr(t)ŷ(t); ẑ(t))j � � ; a � � < � <1: (1) Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 375 V.M. Bruk It follows from "method of the variation of arbitrary constants" that general solution of the equation l[y]� � ~A(t)y = ~A(t)f(t) is represented in the form: y(t) = W (t; �) 0 @c+ J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds 1 A ; (2) where c 2 Hr. Consequently, ŷ(t) = Ŵ (t; �) 0 @c+ J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds 1 A : (3) 3. Construction of a Space Containing the Range of the Characteristic Operator Function M(�) Let Q0 be a set of elements c 2 Hr such that function W (t; 0)c is identi�ed with zero in the space B, i.e., 1R a A1=2(s)W (s; 0)c 2 ds = 0. It follows from the equalities W (t; �)c = W (t; 0) 0 @c+ �J�1r (a) tZ a W �(s; 0) ~A(s)W (s; �)cds 1 A ; (4) W (t; 0)c = W (t; �) 0 @c� �J�1r (a) tZ a W �(s; ��) ~A(s)W (s; 0)cds 1 A (5) that the function W (t; �)c is identi�ed with zero in the space B if and only if c 2 Q0 (in the �nite-dimensional case this fact was obtained in [7]). By Q we denote an orthogonal complement of Q0 in Hr, Hr = Q�Q0. Let [a; �m],m = 1; 2; : : : , be a system of intervals such that [a; �m] � [a; �m+1) and �m ! 1 as m ! 1. We denote Bm = L2(H;A(t); a; �m). Suppose Q0(m) is the set of elements c 2 Q such that the function W (t; �)c is identi�ed with zero in the space Bm, i.e., �mR a A1=2(s)W (s; �)c 2 ds = 0. It follows from (4), (5) that Q0(m) does not depend on �. Let Q(m) be the orthogonal complement of Q0(m) 376 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... in Q, i.e., Q = Q(m) �Q0(m). Obviously, Q0(1) � Q0(2) � : : : � Q0(m) � : : : and Q(1) � Q(2) � : : : � Q(m) � : : : � Q. We de�ne the quasiscalar product (c; d) (i) � = �iZ a ( ~A(s)W (s; 0)c;W (s; 0)d)ds; c; d 2 Q; in space Q. This quasiscalar product generates the semi-norm kck (i) � = 0 @ �iZ a A1=2(s)W (s; 0)c 2 ds 1 A 1=2 � kck ; c 2 Q; = (i) > 0: (6) Clearly, k�ki � � k�k i+1 � . Note that if c 2 Q(m), then kck (m) � > 0 for c 6= 0. Therefore the semi-norm k�k i � is a norm on the set Q(m) for i � m. By Q (i) � (m) we denote the completion of Q(m) with respect to this norm. It follows from (4), (5) that we obtain the same set Q (i) � (m) with the equivalent norm whenever we replace W (s; 0) by W (s; �) in (6). The inclusion map Q (k) � (m) � Q (i) � (m) is continuous for k � i � m. We denote Q � (m) = Q (m) � (m). Let ker(a; �m; �) be a closure of the set of elements (i.e., of classes of functions) in the space Bm with the representatives of the form W (t; �)x, where x 2 Q(m). (We denote these classes by ~W (t; �)x.) It follows from (4�6) that the operator c! ~W (t; �)c (c 2 Q � (m)) is the continuous one-to-one mapping of Q � (m) onto ker(a; �m; �). By Wm(�) we denote this operator. Here ~W (t; �)c is the class of functions such that the sequence f ~W (t; �)ckg converges to ~W (t; �)c in the space Bm whenever fckg converges to c in the space Q � (m). By Q(n;m) we denote the orthogonal complement of Q(m) in Q(n) for n > m, i.e., Q(n) = Q(m)�Q(n;m). Then Q � (n) = Q (n) � (m) _+Q (n) � (n;m); (7) where Q (n) � (n;m) is the completion of Q(n;m) with respect to the norm k�k (n) � . Hence denoting ker(Q(m); a; �n; �) = Wn(�)Q (n) � (m); ker(Q(n;m); a; �n; �) = Wn(�)Q (n) � (n;m); we obtain ker(a; �n; �) = ker(Q(m); a; �n; �) _+ ker(Q(n;m); a; �n; �): (8) Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 377 V.M. Bruk We de�ne the linear mappings gmn : ker(a; �n; �) ! ker(a; �m; �) (n � m) in the following way. Let gmnz = Wm(�)jmnW �1 n (�)z for z 2 ker(Q(m); a; �n; �) and gmnz = 0 for z 2 ker(Q(n;m); a; �n; �) (here jmn is the inclusion map of Q (n) � (m) into Q � (m)). It follows from (7), (8) and the properties of the operators Wk(�) that mappings gmn are continuous. Moreover, we introduce the linear mappings hmn : Q � (n) ! Q � (m) (n � m) in accordance with (7) in the following way. Since the inclusion map of Q (n) � (m) into Q � (m) is continuous, we de�ne hmnc = jmnc whenever c 2 Q (n) � (m), and we de�ne hmnc = 0 whenever c 2 Q (n) � (n;m). Mappings hmn are continuous. By ker(a;1; �) we denote a projective limit of the family fker(a; �n; �); n 2Ng with respect to mappings gmn and by Q� we denote a projective limit of the family fQ � (n));n 2Ng with respect to mappings hmn, i.e., ker(a;1; �) = lim(pr)gmn ker(a; �n; �); Q � = lim(pr)hmnQ�(n): It follows from the de�nition of projective limit [10, Ch. 2] that Q � is a sub- space of the product Q n Q � (n) and Q � consists of the elements c = fcng such that cm = hmncn for all m � n. Similarly, ker(a;1; �) is a subspace of Q n ker(a; �n; �) and the analogous statement is true in regard to ker(a;1; �). By pn, p 0 n we de- note the projections Q n Q � (n) and Q n ker(a; �n; �) onto Q � (n) and ker(a; �n; �) respectively. The mappings gmn, hmn and the operators Wn(�) : Q � (n) ! ker(a; �n; �) satisfy the equality: gmn = Wm(�)hmnW �1 n (�). Consequently, the family of operators fWn(�)g generates the isomorphism (i.e., the linear homeomorphism) W (�) : Q � ! ker(a;1; �). If c = fcng 2 Q n Q � (n), then W (�)c = fWn(�)cng and W (�)Q � = ker(a;1; �). Moreover, p0n(W (�)Q � ) = Wn(�)pn(Q�): (9) Lemma 1. Let wn be a representative of the class of functions ~wn = Wn(�)d (d 2 Q � (n)) and let wm be restriction of wn to [a; �m] (m � n). Then ~wm = Wm(�)hmnd: (10) P r o o f. According to (7) we represent d in the form d = d0 + d00, where d0 2 Q (n) � (m) � Q � (m), d00 2 Q (n) � (n;m). Suppose the sequences fd0 k g, fd00 k g (d0 k 2 Q(m), d00 k 2 Q(n;m)) converge to d0, d00 in the spaces Q (n) � (m), Q (n) � (n;m) respectively. Then the sequence f ~W (t; �)d0 k g converges to Wn(�)d 0 in the space Bn. Therefore f ~W (t; �)d0 k g converges to Wm(�)jmnd 0 in Bm and the functions W (t; �)d00 k are identi�ed with zero in Bm. Hence follows (10). Lemma 1 is proved. 378 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... Let c0 2 Hr. Then the function ~A1=2(t)W (t; �)c0 belongs to L2(H; a; �n) for all n and ~A1=2(t)W (t; �)c0 coincides with ~A1=2(t)W (t; �)c00 in this space, where c00 = PnP0c 2 Q(n), P0 is the orthogonal projection of Hr onto Q, Pn is the orthogonal projection of Q onto Q(n). Suppose the sequence fdkg, dk 2 Q(n), converges to d in the space Q � (n); then classes of functions ~W (t; �)dk 2 Bn with the representatives of W (t; �)dk converge to the class of functions ~W (t; �)d in Bn. Therefore functions ~A1=2(t)W (t; �)dk converge to the function z(t) = ~A1=2(t) ~W (t; �)d in the space L2(H; a; �n). It follows from (10) that the restriction of z(t) to the interval [a; �m], m < n, coincides with ~A1=2(t) ~W (t; �)hmnd. Suppose c = fcng 2 Q � ; then cm = hmncn (m � n). It follows from (10) that the restriction of function ~A1=2(t) ~W (t; �)cn to the interval [a; �m] coin- cides with the function ~A1=2(t) ~W (t; �)cm in the space L2(H; a; �m). Therefore by ~A1=2(t) ~W (t; �)c we denote the function coinciding with ~A1=2(t) ~W (t; �)cn on any interval [a; �n]. Correspondingly, by ~W (t; �)c we denote the H �1=2(t)�G(t)- valued function coinciding with ~W (t; �)cn in the spaces Bn for all n. It follows from (9), (10) that ~W (t; �)cn = ~W (t; �)cm in the space Bm, m � n. 4. Construction of a Domain of the Characteristic Operator Function M(�) The space Q � (n) can be treated as a negative one with respect to Q(n). By Q+(n) we denote a corresponding space with the positive norm. It follows from (7) that Q+(n) = Q (n) + (m) _+Q (n) + (n;m), where Q (n) + (m), Q (n) + (n;m) are the corresponding positive spaces with respect to Q (n) � (m), Q(m) and Q (n) � (n;m), Q(n;m). The inclusion Q+(m) � Q (n) + (m) is dense and continuous. Consequently the inclusion map of Q+(m) into Q+(n) is continuous for m � n. Suppose h+nm : Q+(m) ! Q+(n), n � m, is the adjoint mapping of hmn; then h+nm is the continuous inclusion map of Q+(m) into Q+(n). By Q+ we denote inductive limit [10, Ch. 2] of the family fQ+(n);n 2 Ng with respect to mappings h+nm, i.e., Q+ = lim(ind)h+nmQ+(n). It follows from [10, Ch. 4] that Q+ is the adjoint space of Q � . The space Q+ can be treated as the union Q+ = S n Q+(n) with the strongest topology such that all inclusion maps of Q+(n) into Q+ are continuous [10, Ch. 2]. Let ~y 2 Bm and m � n. Suppose y is a representative of the class of func- tions ~y, then we can treat ~y as an element of the space Bn whenever we extend y by zero out of the interval [a; �m]. If m � n, then the space Bm can be treated as a subspace Bn. The topology of Bm is induced by the topology of Bn. Let inm be the inclusion map of Bm into Bn. By ~B we denote the inductive limit of the spaces Bn with respect to the mappings inm, i.e., ~B = lim(ind)inmBn. The Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 379 V.M. Bruk space ~B can be treated as ~B = S n Bn with the strongest topology such that all inclusion maps of Bn into ~B are continuous. Suppose fFng, n 2 N, is a family of locally convex spaces such that Fm � Fn for m � n and this inclusion map is continuous. According to [8, Ch. 1], an inductive limit F = lim(ind)Fn of the locally convex spaces Fn, n 2 N, is called a regular one if for every bounded set S � F there is n 2 N such that S � Fn and S is a bounded set in Fn. It follows from [8, Ch. 1] that the inductive limits Q+ and ~B are regular. According to [10, Ch. 2], the inductive limit of bornological spaces is a bornological space. Since Q+, ~B are the inductive limits of the re�exive Banach spaces, we see that Q+, ~B are bornological. Suppose Fn are bornological spaces such that their inductive limit F is regular. Let F0 be a locally convex space. It follows from [10, Ch. 2] that a linear mapping u : F ! F0 is continuous if and only if for every n 2 N restriction of u to Fn maps every bounded set S � Fn into the bounded set u(S) � F0. According to [10, Ch. 2, Ex. 17], we can take a bounded sequence instead of the bounded set S � Fn. Further, these statements will be used for the proof of the continuity of corresponding operators. We take the space Q � instead of F0. Then the following conditions are equivalent: (i) the set u(S) is bounded in Q � ; (ii) the sets pku(S) are bounded in the spaces pkQ� = Q � (k) for every k 2 N; (iii) the sets Wk(�)pku(S) are bounded in the spaces Bk for every k 2 N; (iiii) the sets consisting of elements of the form ~W (t; �)ck are bounded for every k 2 N, where ck 2 pku(S) � Q � (k). Thus the following lemma is proved. Lemma 2. Suppose the spaces Fn are bornological and their inductive limit F is regular. The linear operator u : F ! Q � is continuous if and only if for every n 2 N and every bounded set S � Fn and every k 2 N the sets consisting of elements of the form ~W (t; �)ck are bounded in Bk, where ck 2 pku(S) � Q � (k). Any bounded sequence can be taken in place of bounded set S. Further, we shall take a family of space fQ+(n)g or fBng in place of fFng. Then F = Q+ or F = ~B respectively. As it was mentioned above, the operator Wn(�) is a continuous one-to-one mapping of Q � (n) onto the closed subspace ker(a; �n; �) of the space Bn. Then the adjoint operatorW � n(�) maps continuously Bn onto Q+(n). Therefore W � n(�) is the continuous operator of Bn into Q+. The operator W � n(�) has the following form: W � n(�) ~f = �nZ a W �(s; �) ~A(s)f(s)ds = 1Z a W �(s; �) ~A(s)f(s)ds; (11) where ~f 2 B and f vanishes outside [a; �n]. 380 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... We note that the norms W �(s; �)A1=2(s) , A1=2(s)f(s) belong to L2(a; �n). Hence the integral in the right side of (11) exists. Since ~B consists of �nite functions, in accordance with (11) we can de�ne the operator W � (�) mapping ~B onto Q+ by the formula W � (�) ~f = 1Z a W �(s; ��) ~A(s)f(s)ds: It follows from the reasoning given before Lemma 2 that the operator W � (�) : ~B ! Q+ is continuous. Obviously, W � (�) ~f = W � n( ��) ~f for ~f 2 Bn. 5. The Main Result To prove the main theorem we need several lemmas. Lemma 3. ~g 2 B belongs to the range R(L00� ��E) of the relation L00� ��E if and only if there is an interval (a; �n) such that g is �nite on (a; �n) and �nZ a W �(s; �) ~A(s)g(s)ds = 0: (12) P r o o f. Let g be �nite and (12) is true. We denote z(t) = W (t; ��) 0 @J�1r (a) tZ a W �(s; �) ~A(s)g(s)ds 1 A : From (2), (3), (12) we obtain that the ordered pair f~z; ~gg 2 L00 � ��E. Vice versa, let f~z; ~gg 2 L00 � ��E. It follows from (2), (3) that there is a rep- resentative z of the class of functions ~z such that the equality ẑ(t) = Ŵ (t; ��) 0 @c+ J�1r (a) tZ a W �(s; �) ~A(s)g(s)ds 1 A is true, where c 2 Q. Since the function z is �nite, we see that c = 0 and g is �nite on some interval (a; �n) and equality (12) is true. Lemma 3 is proved. R e m a r k. In Lemma 3 we can replace the interval (a; �n) by any interval such that the function z vanishes out of this interval, where f~z; ~gg 2 L00 � ��E. Equality (12) and the equality (~g; ~W (t; �)c)Bn = 0 are equivalent for all c 2 Q � (n). Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 381 V.M. Bruk Lemma 4. If the ordered pair f~y; ~fg 2 L�0��E, then ~y can be represented in the following form: ~y(t) = ~W (t; �)c + ~W (t; �)J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds = ~W (t; �) 0 @c+ J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds 1 A ; (13) where c 2 Q � . P r o o f. We denote u(t) = W (t; �) 0 @J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds 1 A : Let f~z; ~gg 2 L00 � ��E and z(t) = 0 for t � �n. From Lagrange's formula (1), we obtain �nZ a ( ~A(s)g(s); u(s))ds � �nZ a ( ~A(s)z(s); f(s))ds = 0: The equality �nZ a ( ~A(s)g(s); y(s))ds � �nZ a ( ~A(s)z(s); f(s))ds = 0 is true for every ordered pair f~y; ~fg 2 L�0 � �E. It follows from the last two equalities that (~g; ~y � ~u)Bn = 0. Since ker(a; �n; �) is closed and g 2 R(L00 � �E) is arbitrary, from Lemma 3 and remark we obtain the equality ~y� ~u = ~W (t; �)cn. Since the interval (a; �n) is taken arbitrarily, we obtain (13) where c = fcng 2 Q � . Note that Lemmas 3, 4 follow also from paper: V.M. Bruk, J. Math. Phys., Anal., Geom. 2 (2006), 1�10. Theorem. Every generalized resolvent R�, Im� 6= 0, of the relation L0 is the integral operator R� ~f = 1Z a K(t; s; �) ~A(s)f(s)ds ( ~f 2 B): The kernel K(t; s; �) has the form K(t; s; �) = ~W (t; �)(M(�) � (1=2)sgn(s� t)J�1r (a))W �(s; ��); 382 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... where M(�) : Q+ ! Q � is the continuous operator such that M(��) = M�(�) and (Im�)�1Im(M(�)x; x) � 0 (14) for every �xed �, Im� 6= 0, and for every x 2 Q+. The operator function M(�)x is holomorphic for every x 2 Q+ in the semi-planes Im� 6= 0. P r o o f. First, we prove the theorem for the functions �nite on (a;1) . Suppose ~f 2 B and f is a �nite function. It follows from (13) that ~y = R� ~f has the following form: ~y = ~y(t; ~f; �) = ~W (t; �) 0 @c( ~f; �) + (1=2)J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds � (1=2)J�1r (a) 1Z t W �(s; ��) ~A(s)f(s)ds 1 A ; (15) where c( ~f; �) 2 Q � and c( ~f; �) is uniquely determined by ~f and �, Im� 6= 0. Indeed, if it is not so, then ~W (t; �)c( ~f ; �) = R�0 = 0, and this equality is true whenever c( ~f; �) = 0. Therefore, c( ~f; �) = C(�) ~f where C(�) : ~B ! Q � is the linear operator. Now we show that the operator C(�) is continuous for every �xed �. Let the sequence f ~fkg ( ~fk 2 Bn) be bounded in Bn for a �xed number n 2 N. Then f ~fkg is bounded in B. Hence the sequence fR� ~fkg is bounded in B. Consequently, fR� ~fkg is bounded in Bm. It follows from (15) that the sequence f ~W (t; �)pmc( ~fk; �)g is bounded in Bm. Since n;m 2 N are arbitrary and according to Lemma 2, it follows that the operator C(�) is continuous. Now we prove that c( ~f; �) is uniquely determined by the element W � (�) ~f 2 Q+. We assume that W � (�) ~f = 0. Then the ordered pair f~z; ~fg 2 L0 � �E, where ~z(t) = ~W (t; �) 0 @(1=2)J�1r (a) tZ a W �(s; ��) ~A(s)f(s)ds � (1=2)J�1r (a) 1Z t W �(s; ��) ~A(s)f(s)ds 1 A : Since (L0 � �E)�1 � R�, we obtain that ~W (t; �)c( ~f ; �) belongs to the range of the operator R�. Hence c( ~f; �) = 0. Thus C(�) = M(�)W � (�) ~f , where M(�) : Q+ ! Q � is an everywhere de�ned operator. We prove that M(�) is continuous for every �xed �. Let the sequence fqkg = fW � (�) ~fkg be bounded in Q+(n). By B (0) n we denote the orthogonal Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 383 V.M. Bruk complement of kerW � n(�) in the space Bn. The operator W � n(�) is a continuous one-to-one mapping of B (0) n onto Q+(n). Consequently, there exists a bounded sequence f~gkg (~gk 2 B (0) n ) in Bn such that qk = W � (�) ~fk = W � n(�)~gk. Then the sequence fR�~gkg is bounded in B. Consequently, fR�~gkg is bounded in Bm for every m 2 N. Hence the sequence f ~W (t; �)pmM(�)qkg is bounded in Bm. It follows from Lemma 2 that the operator M(�) is continuous. Now we prove that the function M(�)x is holomorphic (Im� 6= 0) for every x 2 Q+. It follows from (15) and holomorphicity of R� that the function � ! ~W (t; �)pnC(�) ~f is holomorphic in Bn for every ~f 2 Bj , n; j 2 N. Substitu- ting pnC(�) ~f for c in equality (4), we get that function � ! ~W (t; 0)pnC(�) ~f is holomorphic. Since the operator x ! ~W (t; 0)x is a continuous one-to-one mapping of Q � (n) onto ker(a; �n) and ker(a; �n) is closed in Bn, we obtain that � ! pnC(�) ~f = pnM(�)W � j (��) ~f is the holomorphic function for every ~f 2 Bj . Now holomorphicity of function � ! pnM(�)x follows from the lemma proved in [11]. Lemma 5. Suppose bounded operators S3(�) : B1 ! B3, S1(�) : B1 ! B2, S2(�) : B2 ! B3 satisfy the equality S3(�) = S2(�)S1(�) for every �xed � belon- ging to some neighborhood of a point �0 and suppose the range of operator S1(�0) coincides with B2, where B1, B2, B3 are Banach spaces. If functions S1(�), S3(�) are strongly di�erentiable in the point �0, then in this point function S2(�) is strongly di�erentiable. In this lemma it should be taken that B1 = Bj , B2 = Q+(j), B3 = Q � (n), S1(�) = W � j (��), S2(�) = pnM(�), S3(�) = pnC(�). So, the operator function � ! pnM(�)x is strongly di�erentiable for every n 2 N and for every x 2 Q+. Now holomorphicity of the operator function M(�)x for every x 2 Q+ follows from the closeness of Q � in the product of spaces Q � (n) [10, Ch. 2] and from the de�nition of topology of the product space. It follows from the equality R� � = R�� that M(��) = M�(�) and ~A1=2(s)K�(t; s; �)A1=2(t) = ~A1=2(s)K(s; t; ��)A1=2(t): (16) Now we show inequality (14). First, we prove the following statement. Lemma 6. Suppose ~u; ~u0; ~v; ~v0 2 Bn satisfy the equalities ~u(t) = ~W (t; �)(c + J�1r (a) tR a W �(s; ��) ~A(s)u0(s)ds); ~v(t) = ~W (t; �)(d + J�1r (a) tR a W �(s; ��) ~A(s)v0(s)ds); (17) 384 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... where d 2 Q � (n), c = �J�1r (a) �nR a W �(s; ��) ~A(s)u0(s)ds. Then �nZ a ( ~A(t)u0(t); v(t))dt � �nZ a ( ~A(t)u(t); v0(t))dt = �(Jr(a)c; d) � (�� ��) �nZ a ( ~A(t)u(t); v(t))dt: (18) P r o o f. Since Jr(a)c 2 Q+(n), we see that the right-hand side (18) exists. Let dk 2 Q(n) and the sequence fdkg converges to d as k ! 1 in the space Q � (n). If we replace d by dk in (17), then we obtain the function denoted by ~vk(t). The sequence f~vkg converges to ~v in the space Bn. We apply Lagrange's formula (1) to the functions u, vk. From the equalities û(�n) = 0, ~A(t)u0(t) = l[u]�� ~A(t)u, ~A(t)v0(t) = l[vk]�� ~A(t)vk, we obtain the equality of the form (18), where v is replaced by vk. By calculating to the limit as k !1, we obtain (18). The lemma is proved. In order to prove inequality (14), we take the arbitrary element x 2 Q+. Then there is n 2 N such that x 2 Q+(n). Consequently, there exists ~f 2 Bn such that �nZ a W �(s; ��) ~A(s)f(s)ds = W � (�) ~f = x: Let ~z(t) = ~W (t; �)(M(�)x + (1=2)J�1r (a)x). Suppose ~y = R� ~f has the form of (15), where c( ~f; �) = M(�)x. Having made some elementary transformations we can apply Lemma 6 to the functions ~u = ~y � ~z, ~u0 = ~f , ~v = ~y + ~z, ~v0 = ~f . Then we have �nR a ( ~A(t)f; z + y)dt� �nR a ( ~A(t)(y � z); f)dt = 2(x;M(�)x) � (�� ��) �nR a ( ~A(t)(y � z); y + z)dt: Consequently, (Im�)�1Im(M(�)x; x) = (z; z)Bn + f(�� ��)�1[(R� ~f; ~f)Bn � ( ~f;R� ~f)Bn ]� (R� ~f;R� ~f)Bn g: (19) The operator function R� is a generalized resolvent of the minimal relation generated in the space Bn by the expression l and the function A(t) (the proof is similar to the proof of the corresponding statement for the operator from [1]). Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 385 V.M. Bruk Consequently, the addend in �gurate brackets in the right-hand side (19) is non- negative. Now (14) follows from (19). Now we assume that ~f 2 B is not �nite, in general. By V1 we denote the ope- rator x! ~W (t; �)(M(�)x + (1=2)J�1r (a)x). The operator V1 maps continuously Q+(n) into B for every n 2 N. Indeed, for any bounded sequence fxkg in Q+(n) there exists a bounded sequence f~gkg (~gk 2 B (0) n ) in Bn such that xk =W � n(�)~gk. Then the sequence fR�~gkg is bounded in B. The functions gk vanish out of the interval [a; �n]. Consequently, the equality R�~gk = ~W (t; �)(M(�)xk + (1=2)J�1r (a)xk) is true out of the interval [a; �n]. Therefore the sequence f ~W (t; �)(M(�)xk + (1=2)J�1r (a)xk)g is bounded in the space B. This implies that the operator V1 is continuous. Hence we obtain the inequality 1Z a ( ~A(t) ~W (t; �)(M(�)x + (1=2)J�1r (a)x; ~W (t; �)(M(�)x + (1=2)J�1r (a)x)dt � k(n; �) kxk2 Q+(n) ; k(n; �) > 0: (20) Now suppose ~f 2 B and f is a non�nite function, in general. We take the sequence f ~fng converging to ~f in the space B, where ~fn 2 B and functions fn are �nite. Using (20) and (16), we obtain that for every �nite function g (~g 2 B) there exists the limit lim n!1 1R a ( ~A1=2(t) 1R a K(t; s; �) ~A(s)fn(s)ds; ~A 1=2(t)g(t))dt = lim n!1 1R a ( ~A1=2(s)fn(s); ~A 1=2(s) 1R a K(s; t; ��) ~A(t)g(t)dt) = 1R a ( ~A1=2(s)f(s); ~A1=2(s) 1R a K(s; t; ��) ~A(t)g(t)dt): Hence the sequence � 1R a K(t; s; �) ~A(s)fn(s)ds � converges to R� ~f as n ! 1 at least weakly in the space B. The theorem is proved. References [1] A.V. Straus, On the Generalized Resolvents and Spectral Functions of the Di�er- ential Operator of the Even Order. � Izv. Acad. Nauk SSSR. Ser. Mat. 21 (1957), No. 1, 785�808. (Russian) [2] V.M. Bruk, On the Generalized Resolvents and Spectral Functions of the Di�erential Operator of the Even Order in the Space of Vector Functions. � Mat. Zametki 15 (1974), No. 6, 945�954. (Russian) 386 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 4 Generalized Resolvents of Symmetric Relations Generated on Semi-Axis... [3] V.M. 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