Relative symmetric polynomials and money change problem

This article is devoted to the number of non-negative solutions of the linear Diophantine equation a₁t₁ + a₂t₂ + ⋯ + antn = d, where a₁,…,an, and d are positive integers. We obtain a relation between the number of solutions of this equation and characters of the symmetric group, using relative symme...

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Дата:2013
Автор: Shahryari, M.
Формат: Стаття
Мова:English
Опубліковано: Інститут прикладної математики і механіки НАН України 2013
Назва видання:Algebra and Discrete Mathematics
Онлайн доступ:http://dspace.nbuv.gov.ua/handle/123456789/152353
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Назва журналу:Digital Library of Periodicals of National Academy of Sciences of Ukraine
Цитувати:Relative symmetric polynomials and money change problem / M. Shahryari // Algebra and Discrete Mathematics. — 2013. — Vol. 16, № 2. — С. 287–292. — Бібліогр.: 3 назв. — англ.

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spelling irk-123456789-1523532019-06-11T01:24:59Z Relative symmetric polynomials and money change problem Shahryari, M. This article is devoted to the number of non-negative solutions of the linear Diophantine equation a₁t₁ + a₂t₂ + ⋯ + antn = d, where a₁,…,an, and d are positive integers. We obtain a relation between the number of solutions of this equation and characters of the symmetric group, using relative symmetric polynomials. As an application, we give a necessary and sufficient condition for the space of the relative symmetric polynomials to be non-zero. 2013 Article Relative symmetric polynomials and money change problem / M. Shahryari // Algebra and Discrete Mathematics. — 2013. — Vol. 16, № 2. — С. 287–292. — Бібліогр.: 3 назв. — англ. 1726-3255 2010 MSC:Primary 05A17, Secondary 05E05 and 15A69. http://dspace.nbuv.gov.ua/handle/123456789/152353 en Algebra and Discrete Mathematics Інститут прикладної математики і механіки НАН України
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
collection DSpace DC
language English
description This article is devoted to the number of non-negative solutions of the linear Diophantine equation a₁t₁ + a₂t₂ + ⋯ + antn = d, where a₁,…,an, and d are positive integers. We obtain a relation between the number of solutions of this equation and characters of the symmetric group, using relative symmetric polynomials. As an application, we give a necessary and sufficient condition for the space of the relative symmetric polynomials to be non-zero.
format Article
author Shahryari, M.
spellingShingle Shahryari, M.
Relative symmetric polynomials and money change problem
Algebra and Discrete Mathematics
author_facet Shahryari, M.
author_sort Shahryari, M.
title Relative symmetric polynomials and money change problem
title_short Relative symmetric polynomials and money change problem
title_full Relative symmetric polynomials and money change problem
title_fullStr Relative symmetric polynomials and money change problem
title_full_unstemmed Relative symmetric polynomials and money change problem
title_sort relative symmetric polynomials and money change problem
publisher Інститут прикладної математики і механіки НАН України
publishDate 2013
url http://dspace.nbuv.gov.ua/handle/123456789/152353
citation_txt Relative symmetric polynomials and money change problem / M. Shahryari // Algebra and Discrete Mathematics. — 2013. — Vol. 16, № 2. — С. 287–292. — Бібліогр.: 3 назв. — англ.
series Algebra and Discrete Mathematics
work_keys_str_mv AT shahryarim relativesymmetricpolynomialsandmoneychangeproblem
first_indexed 2025-07-13T02:53:37Z
last_indexed 2025-07-13T02:53:37Z
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fulltext Algebra and Discrete Mathematics RESEARCH ARTICLE Volume 16 (2013). Number 2. pp. 287 – 292 c© Journal “Algebra and Discrete Mathematics” Relative symmetric polynomials and money change problem M. Shahryari Communicated by V. A. Artamonov Abstract. This article is devoted to the number of non- negative solutions of the linear Diophantine equation a1t1 + a2t2 + · · · + antn = d, where a1, . . . , an, and d are positive integers. We obtain a relation between the number of solutions of this equation and characters of the symmetric group, using relative symmetric polynomials. As an application, we give a necessary and sufficient condition for the space of the relative symmetric polynomials to be non-zero. Suppose a1, . . . , an, and d are positive integers, and consider the fol- lowing linear Diophantine equation: a1t1 + a2t2 + · · · + antn = d. Let Qd(a1, . . . , an) be the number of non-negative integer solutions of this equation. Computing the exact values of the function Qd is the well-known money change problem. It is easy to see that a generating function for Qd(a1, . . . , an) is n∏ i=1 1 1 − tai . This article is devoted for an interesting relation between Qd and ir- reducible complex characters of the symmetric group Sm, where m = a1 + · · · + an. In fact, we will show that Qd is a permutation character of 2010 MSC: Primary 05A17, Secondary 05E05 and 15A69. Key words and phrases: Money change problem; Partitions of integers; Relative symmetric polynomials; Symmetric groups; Complex characters. 288 Money change problem Sm, and then we will find its irreducible constituents. Our main tool, in the investigation of Qd, is the notion of relative symmetric polynomials, which is introduced by the author in [3]. Once, we find the irreducible constituents of Qd, we can also obtain a necessary and sufficient condition for vanishing of the space of relative symmetric polynomials. A similar result was obtained in [2], for vanishing of symmetry classes of tensors, using the same method. We need a survey of results about relative symmetric polynomials in this article. For a detailed exposition, one can see [3]. Let G be a subgroup of the full symmetric group Sm of degree m and suppose χ is an irreducible complex character of G. Let Hd[x1, . . . , xm] be the complex space of homogenous polynomials of degree d with the independent commuting variables x1, . . . , xm. Suppose Γ+ m,d is the set of all m-tuples of non-negative integers, α = (α1, . . . , αm), such that∑ i αi = d. For any α ∈ Γ+ m,d, define Xα to be the monomial xα1 1 · · ·xαm m . So the set {Xα : α ∈ Γ+ m,d} is a basis of Hd[x1, . . . , xm]. We define also an inner product on Hd[x1, . . . , xm] by < Xα, Xβ >= δα,β . The group G acts on Hd[x1, . . . , xm] via qσ(x1, . . . , xm) = q(xσ−1(1), . . . , xσ−1(m)). It also acts on Γ+ m,d by σα = (ασ(1), . . . , ασ(m)). Let ∆ be a set of representatives of orbits of Γ+ m,d under the action of G. Now consider the idempotent T (G,χ) = χ(1) |G| ∑ σ∈G χ(σ)σ in the group algebra CG. Define the space of relative symmetric polyno- mials of degree d with respect to G and χ to be Hd(G,χ) = T (G,χ)(Hd[x1, . . . , xm]). Let q ∈ Hd[x1, . . . , xm]. Then we set q∗ = T (G,χ)(q) M. Shahryari 289 and we call it a symmetrized polynomial with respect to G and χ. Clearly Hd(G,χ) =< Xα,∗ : α ∈ Γ+ m,d >, where < set of vectors > denotes the subspace generated by a given set of vectors. Recall that the inner product of two characters of an arbitrary group K is defined as follows, [φ, ψ]K = 1 |K| ∑ σ∈K φ(σ)ψ(σ−1). In the special case where K is a subgroup of G and φ and ψ are characters of G, the notation [φ, ψ]K will denote the inner product of the restrictions of φ and ψ to K. It is proved it [3] that for any α, we have ||Xα,∗||2 = χ(1) [χ, 1]Gα [G : Gα] , where Gα is the stabilizer subgroup of α under the action of G. Hence, Xα,∗ 6= 0, if and only if [χ, 1]Gα 6= 0. According to this result, let Ω be the set of all α ∈ Γ+ m,d, with [χ, 1]Gα 6= 0 and suppose ∆̄ = ∆ ∩ Ω. We proved in [3], the following formula for the dimension of Hd(G,χ) dimHd(G,χ) = χ(1) ∑ α∈∆̄ [χ, 1]Gα . Note that, ∆̄ depends on χ, but ∆ depends only on G. Since, [χ, 1]Gα = 0, for all α ∈ ∆ − ∆̄, we can re-write the above formula, as dimHd(G,χ) = χ(1) ∑ α∈∆ [χ, 1]Gα . There is also another interesting formula for the dimension ofHd(G,χ). This is the formula which employs the function Qd and so it connects the money change problem to relative symmetric polynomials. Let σ ∈ G be any element with the cycle structure [a1, . . . , an], ( i.e. σ is equal to a product of n disjoint cycles of lengths a1, . . . , an, respectively). Define Qd(σ) to be the number of non-negative integer solutions of the equation a1t1 + a2t2 + · · · + antn = d, 290 Money change problem so, we have Qd(σ) = Qd(a1, . . . , an). If we consider the free vector space C[Γ+ m,d] as a CG-module, then for all σ ∈ G, we have Tr σ = Qd(σ), and hence, Qd is a permutation character of G. It is proved in [3], that we have also dimHd(G,χ) = χ(1) |G| ∑ σ∈G χ(σ)Qd(σ). Note that, we can write this result as dimHd(G,χ) = χ(1)[χ,Qd]G. Now, comparing two formulae for the dimension of Hd(G,χ) and using the reciprocity relation for induced characters, we obtain Qd(a1, . . . , an) = ∑ α∈∆ (1Gα)G(σ), where σ ∈ Sm is any permutation of the cycle structure [a1, . . . , an], G is any subgroup of Sm containing σ and m = a1 + · · · + an. It is clear that, if α and β are in the same orbit of Γ+ m,d, then (1Gα)G = (1Gβ )G, so we have also Qd(a1, . . . , an) = 1 |G| ∑ α∈Γ+ m,d |Gα|(1Gα)G(σ). As our main result in this section, we have, Theorem A. Qd = 1 |G| ∑ α∈Γ+ m,d |Gα|(1Gα)G. For a fixed equation a1t1 + a2t2 + · · · + antn = d, suppose σ is a permutation of the cycle structure [a1, . . . , an] and let G be the cyclic group generated by σ. Clearly this G is the smallest subgroup of Sm which we can use to obtain the number of non-negative solutions of the above equation. By Theorem A, the required number is Qd(σ) = 1 |G| ∑ α∈Γ+ m,d |Gα|(1Gα)G(σ). On the other hand, if we want to have a formula for all values of Qd, we must let G = Sm, which contains any possible cycle structure. So in the remaining part of this article, we will assume that, G = Sm, then M. Shahryari 291 using representation theory of symmetric groups, we will find, irreducible constituents of Qd. We need some standard notions from representation theory of sym- metric groups. Ordinary representations of Sm are in one to one corre- spondence with partitions of m. Let π = (π1, . . . , πs) be any partition of m. The irreducible character of Sm, corresponding to a partition π is denoted by χπ. There is also a subgroup of Sm, associated to π, which is called the Young subgroup and it is defined as, Sπ = S{1,...,π1} × S{π1+1,...,π1+π2} × · · · . Therefore, we have Sπ ∼= Sπ1 × · · · × Sπs . Let π = (π1, . . . , πs) and µ = (µ1, . . . , µl) be two partitions of m. We say that µ majorizes π, iff for any 1 ≤ i ≤ min{s, l}, the inequality π1 + · · · + πi ≤ µ1 + · · · + µi holds. In this case we write λEµ. This is clearly a partial ordering on the set of all partitions of m. A generalized µ-tableau of type π is a function T : {(i, j) : 1 ≤ i ≤ h(µ), 1 ≤ j ≤ µi} → {1, 2, . . . ,m} such that for any 1 ≤ i ≤ m, we have |t−1(i)| = πi. This generalized tableau is called semi-standard if for each i, j1 < j2 implies T (i, j1) ≤ T (i, j2) and for any j, i1 < i2 implies T (i1, j) < T (i2, j). In other words, T is semi-standard, iff every row of T is non-descending and every column of T is ascending. The number of all such semi-standard tableaux is denoted by Kµπ and it is called the Kostka number. It is well known that Kµπ 6= 0 iff µ majorizes π, see [1], for example. We have also, Kµπ = [(1Sπ )Sm , χµ]Sm = [1, χµ]Sπ . For any α ∈ Γ+ m,d, the multiplicity partition is denoted by M(α), so, to obtain M(α), we must arrange the multiplicities of numbers 0, 1, . . . , d in α in the descending order. It is clear that (Sm)α ∼= SM(α), the Young subgroup. If M(α) = (k1, . . . , ks), then we have |(Sm)α| = k1!k2! . . . ks!. 292 Money change problem In what follows, we use the notation M(α)! for the number k1!k2! . . . ks!. On the other hand, we have (1Gα)G = (1SM(α) )Sm = ∑ M(α)Eπ Kπ,M(α)χ π. Now, using Theorem A, we obtain, Theorem B. Qd = 1 m! ∑ α∈Γ+ m,d ∑ M(α)Eπ M(α)!Kπ,M(α)χ π. As a result, we can compute the dimension of Hd(Sm, χ π), in a new fashion. We have, dimHd(Sm, χ π) = χπ(1)[χπ, Qd]Sm = χπ(1) m! ∑ α∈Γ+ m,d ,M(α)Eπ M(α)!Kπ,M(α). Note that, this generalizes the similar formulae in the final part of the second section of [3]. Now, as a final result, we have also, a necessary and sufficient condition for Hd(Sm, χ π) to be non-zero. Theorem C. We have Hd(Sm, χ π) 6= 0, if and only if there exists α ∈ Γ+ m,d, such that M(α) E π. References [1] B. Sagan, The Symmetric Group: Representation, Combinatorial Algorithms and Symmetric Functions, Wadsworth and Brook/ Cole math. series, 1991. [2] M. Shahryari, M. A. Shahabi, On a permutation character of Sm, Linear and Multilinear Algebra, 44 (1998), 45 − 52. [3] M. Shahryari, Relative symmetric polynomials, Linear Algebra and its Applica- tions, 433 (2010), 1410 − 1421. Contact information M. Shahryari Department of Pure Mathematics, Faculty of Mathematical Sciences, University of Tabriz, Tabriz, Iran E-Mail: mshahryari@tabrizu.ac.ir Received by the editors: 08.04.2012 and in final form 28.04.2012.