Finite group with given c-permutable subgroups

Following [1] we say that subgroups H and T of a group G are c-permutable in G if there exists an element x ∈ G such that HTˣ = TˣH. We prove that a finite soluble group G is supersoluble if and only if every maximal subgroup of every Sylow subgroup of G is c-permutable with all Hall subgro...

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Дата:2004
Автор: Ahmad Alsheik Ahmad
Формат: Стаття
Мова:English
Опубліковано: Інститут прикладної математики і механіки НАН України 2004
Назва видання:Algebra and Discrete Mathematics
Онлайн доступ:http://dspace.nbuv.gov.ua/handle/123456789/156463
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Назва журналу:Digital Library of Periodicals of National Academy of Sciences of Ukraine
Цитувати:Finite group with given c-permutable subgroups / Ahmad Alsheik Ahmad // Algebra and Discrete Mathematics. — 2004. — Vol. 3, № 2. — С. 9–16. — Бібліогр.: 12 назв. — англ.

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spelling irk-123456789-1564632019-06-19T01:27:35Z Finite group with given c-permutable subgroups Ahmad Alsheik Ahmad Following [1] we say that subgroups H and T of a group G are c-permutable in G if there exists an element x ∈ G such that HTˣ = TˣH. We prove that a finite soluble group G is supersoluble if and only if every maximal subgroup of every Sylow subgroup of G is c-permutable with all Hall subgroups of G. 2004 Article Finite group with given c-permutable subgroups / Ahmad Alsheik Ahmad // Algebra and Discrete Mathematics. — 2004. — Vol. 3, № 2. — С. 9–16. — Бібліогр.: 12 назв. — англ. 1726-3255 2000 Mathematics Subject Classification: 20D10. http://dspace.nbuv.gov.ua/handle/123456789/156463 en Algebra and Discrete Mathematics Інститут прикладної математики і механіки НАН України
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
collection DSpace DC
language English
description Following [1] we say that subgroups H and T of a group G are c-permutable in G if there exists an element x ∈ G such that HTˣ = TˣH. We prove that a finite soluble group G is supersoluble if and only if every maximal subgroup of every Sylow subgroup of G is c-permutable with all Hall subgroups of G.
format Article
author Ahmad Alsheik Ahmad
spellingShingle Ahmad Alsheik Ahmad
Finite group with given c-permutable subgroups
Algebra and Discrete Mathematics
author_facet Ahmad Alsheik Ahmad
author_sort Ahmad Alsheik Ahmad
title Finite group with given c-permutable subgroups
title_short Finite group with given c-permutable subgroups
title_full Finite group with given c-permutable subgroups
title_fullStr Finite group with given c-permutable subgroups
title_full_unstemmed Finite group with given c-permutable subgroups
title_sort finite group with given c-permutable subgroups
publisher Інститут прикладної математики і механіки НАН України
publishDate 2004
url http://dspace.nbuv.gov.ua/handle/123456789/156463
citation_txt Finite group with given c-permutable subgroups / Ahmad Alsheik Ahmad // Algebra and Discrete Mathematics. — 2004. — Vol. 3, № 2. — С. 9–16. — Бібліогр.: 12 назв. — англ.
series Algebra and Discrete Mathematics
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fulltext Jo u rn al A lg eb ra D is cr et e M at h . Algebra and Discrete Mathematics RESEARCH ARTICLE Number 2. (2004). pp. 9 – 16 c© Journal “Algebra and Discrete Mathematics” Finite group with given c-permutable subgroups Ahmad Alsheik Ahmad Communicated by L. A. Shemetkov Abstract. Following [1] we say that subgroups H and T of a group G are c-permutable in G if there exists an element x ∈ G such that HT x = T xH. We prove that a finite soluble group G is supersoluble if and only if every maximal subgroup of every Sylow subgroup of G is c-permutable with all Hall subgroups of G. Introduction All considered in this paper groups are finite. It is interest to use some information on Sylow subgroups of a group G to determine the structure of the group. For instance, the knowledge of the maximal subgroups of Sylow subgroups often yields wealth of information about the group itself. In [2] Srinivasan proved that G is supersoluble if every maximal subgroup of every Sylow subgroup of G is normal in G. In [3] Wang introduced the concept of c-normality which is a weaker condition than the normality in deriving the same result. In [4,5] the supersolubility of groups in which all maximal subgroups of all Sylow subgroups are complemented was proved. In the paper [6] (see also [7]) Guo, Shum and Skiba proved that a group G is supersoluble if and only if every non-normal in G maximal subgroup of every Sylow subgroup of G has a supersoluble supplement in G. The analogous results for p-nilpetent and p-closed groups were obtained by Kosenok in [8]. In this paper we give in this direction two new characterizations of supersoluble groups appealing to the following concept of c-permutability which was introduced in [1]. 2000 Mathematics Subject Classification: 20D10. Key words and phrases: finite group, maximal subgroup, Sylow subgroup, su- persoluble group, c-permutable subgroup. Jo u rn al A lg eb ra D is cr et e M at h .10 Finite group with given c-permutable subgroups Let H and T be subgroups of a group G. Then, H and T are said to be conditionally permutable (or in brevity, c-permutable) in G if HT x = T xH, for some x ∈ G. The condition of c-permutability is generally weaker than the condi- tion of permutability, for example, one can see that a Sylow 2-subgroup of the simmetric group S3 is not permutable, but it is c-permutable with all subgroups of S3. 1. Preliminaries All considered later on groups are soluble. In this section we give some known results about soluble and supersoluble groups which will be needed in proving our main results later on. The following lemma is well known. Lemma 1. Let H be a Hall π-subgroup of a group G and K E G. Then the following statements hold: (1) HK/K is a Hall π-subgroup of G/K; (2) H ∩ K is a Hall π-subgroup of K; (3) If G = AB for some subgroups A, B of G, then there exist Hall π-subgroup Gπ, Aπ and Bπ in G, A and B respectively such that Gπ = AπBπ. Lemma 2. Let H be a subnormal subgroup of a group G. Then: (1) If H ≤ K ≤ G, then H is subnormal in K; (2) If H is a π-group, then H ≤ Oπ(G) (see [9; Corollary 7.7.2). Now we cite some properties of the supersoluble groups from the literature. Lemma 3. Let G be a group. Then the following statements hold: (i) If G is supersoluble, then G′ ⊆ F (G) and G is p-closed for the largest prime divisor p of |G| (see [10; VI, 9.11]); (ii) If L E G and L/Φ(G) ∩ L is supersoluble, then L is supersoluble (see [9; Corollary 4.2.4]); (iii) G is supersoluble if and only if |G : M | is a prime for every maximal subgroup M of G (see [10; VI, 9.3]). Jo u rn al A lg eb ra D is cr et e M at h .A. Alsheik Ahmad 11 (vi) G is supersoluble if it has two normal subgroups A and B with supersoluble quotients such that A ∩ B = 1. We use the symbol F (G) to denote the Fitting subgroup of a group G (that is the product of all normal nilpotent subgroups of G). Lemma 4 ([11]; A,(10.6)). The Fitting subgroup F (G) of a group G has the following properties: (1) F (G) ≤ CG(H/K) for every chief factor H/K of G; (2) CG(F (G)) ⊆ F (G). Lemma 5. If L E G and L/Φ(G) ∩ L is nilpetent, then L is nilpotent (see [9; Corollary 4.2.1]); Lemma 6 ([1], Lemma 2.1). Let G be a group. Suppose that K E G and H ≤ G. Then: (i) If K ≤ T ≤ G and H is c-permutable with T in G, then KH/K is c-permutable with T/K in G/K; (ii) If K ≤ H, T ≤ G and H/K is c-permutable with KT/K in G/K, then H is c-permutable with T in G. Lemma 7. ([12], Lemma 1.5.6). Let H/K be an abelian chief factor of a group G. Let M be a maximal subgroup of G such that K ⊆ M and MH = G. Then G/MG ' [H/K](G/CG(H/K)). 2. Main results Theorem 1. A soluble group G is supersoluble if and only if it has a non- identity normal subgroup N with supersoluble quotient such that every maximal subgroup of every Sylow subgroup of N is c-permutable with all Hall subgroups of G. Proof. First suppose that G has a non-identity normal subgroup N with supersoluble quotient such that every maximal subgroup of every Sylow subgroup of N is c-permutable with all Hall subgroups of G. We shall show that G is supersoluble. Assume that it is false and let G be a counterexample of minimal order. Then the following statements hold. (a) G/K is supersoluble for every non-identity normal in G sub- group K. Jo u rn al A lg eb ra D is cr et e M at h .12 Finite group with given c-permutable subgroups By hypothesis, it is true if K = N . Let K 6= N . We shall show that the hypothesis of the theorem is true for G/K. First of all we note that KN/N is such a non-identity normal in G/K subgroup that the quotient (G/K)(KN/K) ' G/KN ' (G/N)/(KN/N) is supersoluble. Let P/K be a Sylow p-subgroup of KN/K and P1/K be a maximal in P/K subgroup. Let E/K be a Hall π-subgroup of KN/K. We have to prove that P1/K is c-permutable with E/K. Let R be a Sylow p-subgroup of KN such that RK/K = P/K. By Lemma 1 there exist Sylow p- subgroups Np and Kp in N and K respectively such that R = NpKp. Hence P/K = NpK/K. We will show that P1∩Np is a maximal subgroup of Np. First of all we note that P1 ∩ Np 6= Np. Indeed, if P1 ∩ Np = Np, then Np ⊆ P1 and so P/K = NpK/K = P1/K, this contradicts the choice of the subgroup P1/K. Next assume that G has a subgroup T such that P1 ∩ Np ⊂ T ⊂ Np. Then P1 = K(P1 ∩ Np) ⊆ TK ⊆ KNp = P. But P1 is a maximal subgroup of P and so we have either P1 = TK or TK = KNp. If P1 = TK, we have T ⊆ P1 ∩ Np ⊆ T , that is impossible. Hence TK = NpK and therefore Np = Np ∩ TK = T (Np ∩ K) ⊆ T (P1 ∩ Np) = T, a contradiction. Hence we have to conclude that P1 ∩ Np is a maximal subgroup of Np. By hypothesis it follows that P1 ∩ Np is c-permutable with all Hall subgroups of G. By Lemma 1, G has a Hall π-subgroup Gπ such that E/K = GπK/K. Let x be an element of G such that Gx π(P1 ∩ Np) = (P1 ∩ Np)G x π. Then Gx π(P1 ∩ Np)K/K = Gx πP1/K = (Gx πK/K)(P1/K) = = (E/K)xK(P1/K) = (P1/K)(E/K)xK = (P1 ∩ Np)G x πK/K. (b) If H is a minimal normal subgroup of G, then for some prime p we have H = Op(G) = F (G) = CG(H) * Φ(G) and |H| 6= p. By Lemma 3 and Statement (a), H is the unique minimal normal subgroup of G and H * Φ(G). Let M be a maximal subgroup of G such Jo u rn al A lg eb ra D is cr et e M at h .A. Alsheik Ahmad 13 that H * M . Since G is soluble, H is an elementary abelian p-group for some prime p. Hence G = [H]M . Now let C = CG(H). Then C = C ∩ HM = H(C ∩ M). But, evidently, C ∩ M E G and so C ∩ M = 1. It follows that H = C. Besides, since by Lemma 4 we have F (G) ⊆ C, then H = F (G) = Op(G). It is also clear that |H| 6= p. (c) H is not a Sylow subgroup of N . Suppose that H is a Sylow p-subgroup of N . Let M be a maximal subgroup of H, Q be a Sylow q-subgroup of G where q 6= p. By hypothesis for some x ∈ G we have D = MQx = QxM . Since M is subnormal in G, then by Lemma 2, M is subnormal in D too. But M is a Sylow subgroup of D, and so by Lemma 2, M E D. Hence q - |G : NG(M)|. Thus |G : |G : NG(M)| = pα for some α ∈ {0} ∪ N. But in view of the minimality of H and by Statement (b), NG(M) 6= G. Hence p | |G : NG(M)| and so p | n where n is the number of all maximal in H subgroups. This contradicts Statement 8.5 from [10; III]. So we have (c). (d) N = G. Indeed, suppose that N 6= G. Let Nq be a Sylow subgroup of N , P1 be a maximal subgroup of Nq. And let T be a Hall π-subgroup of N . Let us choose in G a Hall π-subgroup Gπ such that T ⊆ Gπ. Then T = N ∩ Gπ. By hypothesis G has an element x such that D = P1G x π = Gx πP1. It follows that N ∩ D = P1(N ∩ Gx π) = (N ∩ Gx π)P1. But by Lemma 1, N∩Gx π is a Hall π-subgroups of N . Thus every maximal subgroup of every Sylow subgroup of N is c-permutable with all Hall subgroup of N . Thus the hypothesis of this theorem is true for N . But |N | < |G| and so by the choice of G we have to conclude that N is supersoluble. Let q be the largest prime divisor of |N |. Then by Lemma 3, a Sylow q-subgroup Nq of N is normal in N . Since Nq char NEG it follows that Nq E G. Then Nq ⊆ F (G) and hence by (b) we have Nq ⊆ H. Thus Nq = H, this contradicts Statement (c). This contradiction completes the proof of Statements (d). (e) Conclusion contradiction. Let P be a Sylow p-subgroup of G. Then H ⊆ P and by State- ment (c), H 6= P . If H ≤ Φ(P ), then by Statement 3.2 from [10; III], H ⊆ Φ(G), contrary to Statement (b). Hence one can choose in P a maximal subgroup P1 such that H * P1. Let D be a Hall p′- subgroup of G. Then by hypothesis there exists an element x such that T = P1D x = DxP1. It is clear that |G : T | = |P : P1| = p. Besides, Jo u rn al A lg eb ra D is cr et e M at h .14 Finite group with given c-permutable subgroups evidently, H * T and so 1 6= H ∩ T 6= H. But H ∩ T E G, this con- tradicts the minimality of H. This contradiction completes the proof of supersolubility G. Finally suppose that G is a supersoluble group. Let N be a minimal normal subgroup of G. Then |N | = p for some prime p. Thus a maximal subgroup of N is normal in G. Theorem 2. A soluble group G is supersoluble if and only if it has a non- identity normal subgroup N with supersoluble quotient such that every non-complemented in G maximal subgroup of every Sylow subgroup of F (N) is c-permutable with all subgroups of G. Proof. We need only prove the “if” part (see the proof of Theorem 1). Assume that this is false and let G be a counterexample of minimal order. Let Φ be a minimal normal subgroup of G contained in N . Sup- pose that Φ ⊆ Φ(G). Then (since by hypothesis G/N is supersolu- ble) in view of Lemma 3, Φ 6= N . Consider the quitient G/Φ. Let T/Φ = F (N/Φ). Since T/Φ is nilpotent, then by Lemma 5, T is a nilpo- tent normal subgroup of N . Hence T ⊆ F (N). On the other hand, since F (N)/Φ ⊆ F (N/Φ), we have F (N) ≤ T and so T = F (N). Thus F (N/Φ) = T/Φ = F (N)/Φ. Now let P/Φ be a Sylow p-subgroup of T/Φ, M/Φ be a maximal in P/Φ subgroup and Pp be a Sylow p-subgroup of P . Then PpΦ = P and L = M ∩ Pp is a maximal subgroup of Pp (see the proof of Theorem 1). Hence by hypothesis L is either complemented in G or c-permutable with all subgroups of G. Assume we have the first case and let T be a subgroup of G such that G = LT and L∩T = 1. We shall show that then TΦ/Φ is a complement to M/Φ in G/Φ. It is clear that G/Φ = (LΦ/Φ)(TΦ/Φ). Suppose that Φ is a q-group where q 6= p. Then, evidently, Φ ⊆ T and so (LΦ/Φ) ∩ (T/Φ) = (LΦ ∩ T )/Φ = Φ(L ∩ T )/Φ = Φ/Φ . Analogously one can show that TΦ/Φ is a complement to M/Φ in G/Φ in the case when Φ is a p-group. Finally, if we have the second case then by Lemma 6 we see that M/Φ = LΦ/Φ is c-permutable with all subgroups of G/Φ. Therefore G/Φ has a non-identity normal subgroup N/Φ with supersoluble quotient (G/Φ)/(N/Φ) ' G/N such that every non-complemented in G/Φ maximal subgroup of every Sylow subgroup of F (N/Φ) = F (N)/Φ is c-permutable with all subgroups Jo u rn al A lg eb ra D is cr et e M at h .A. Alsheik Ahmad 15 of G/Φ. Thus the hypothesis is true for G/Φ. Since Φ 6= 1, |G/Φ| < |G| and so by the choice of G, G/Φ is supersoluble. But then by Lemma 3, G is supersoluble too, a contradiction. Hence Φ * Φ(G). Thus Φ(G)∩N = 1. Since N EG and F (N) char N , F (N)EG. It follows Φ(F (N)) ⊆ Φ(G) and so Φ(F (N)) = 1. Thus F (N) is an abelian group. Now let D be the least (by inclusion) normal subgroup of G with supersoluble quotient. Then D ≤ N and so if R is a minimal normal subgroup of G contained in D, then R ⊆ F (N). Since Φ(G) ∩ N = 1, G has a maximal subgroup M such that G = [R]M and so |G : M | = |R|. First assume that |R| is a prime. Then by Lemma 7, G/MG ' [RMG/MG]CG(RMG/MG) is a metacyclic group. Hence G/MG is a supersoluble group and so R ⊆ D ⊆ MG ⊆ M. But then G = RM = M . This contradiction shows that |R| is not a prime. Let R1 be a maximal subgroup of R. Then R1 6= 1. Let R be a p-group and D = Op(N). Let us choose a maximal subgroup E of G such that G = ER. Then G = DE and so K = E ∩ D E G. Since, evidently, E ∩R = 1, D = R×K. Let M = R1K. Then since |D : M | = |R : R1| = p, M is a maximal subgroup of D. Hence by hypothesis M is either c-permutable with all subgroups of G or it is complemented in G. If we have the first case, then, in particular, R1KEx = R1E x = ExM for some x ∈ G. It follows that |G : E| = |R1| = |R|. This contradiction shows that we have the second case. Let T be a complement to M in G. It is not difficult to show that V = T ∩D is a group of prime order p. It is clear also that V E G. Because D/K is a chief factor of G and since KV is a normal in G subgroup such that K ⊆ KV ⊆ D, it follows that KV = D and so p = |V | = |D/K| = |R|. This contradiction completes the proof of this theorem. References [1] W. Guo, K.P.Shum and A. N. Skiba, Conditionally Permutable Subgroups and Supersolubility of Finite Groups, Preprint No 49 , Gomel State University, 2003. [2] S.Srinivasan, Two sufficient conditions for supersolubility of finite groups, Israel J. Math., 35, 1990, pp.210-214. [3] Y. Wang, c-Normality of Groups and its Properties, J.Algebra, 78, 1996, pp.101- 108. Jo u rn al A lg eb ra D is cr et e M at h .16 Finite group with given c-permutable subgroups [4] A. Ballester-Bolinches, H. Guo, On complemented subgroups of finite groups, Arch.Math.(Basel), 72, 1999, pp.161-166. [5] Y. Wang, Finite groups with some subgroups of Sylow subgroups c- supplemented , J.Algebra, 224, 224, pp.467- 478. [6] W. Guo, K.P.Shum and A. N. Skiba, G-Covering Subgroup Systems for the Classes of Supersoluble and Nilpotent Groups, Israel J. Math.,138, 2003, pp. 125-138. [7] W. Guo, K.P.Shum and A. N. Skiba, G-Covering Subgroup Systems for the Classes of Supersoluble and Nilpotent Groups, Preprint No 21, Gomel State University, 2001. [8] N. Kosenok, Criterions of p-closure and p-nilpotency of finite groups, Vesty NAN Belarusy, Ser. fiz.-mat. nauk, 4, 2003, pp.68-73. [9] L.A. Shemetkov, Formations of Finite Groups, Nauka, Moscow, 1978. [10] B. Huppert, Endliche Gruppen I, Springer–Verlag, Berlin–Heidelberg–New York, 1979. [11] K. Doerk, O. Hawkes, Finite Soluble Groups, Walter de Gruyter, Berlin-New York, 1992. [12] W. Guo, The Theory of Classes of Groups, Science Press /Kluwer Academic Publishers, Beijing–New York–Dordrecht–Boston–London, 2000. Contact information A. Alsheik Ahmad Belorussian State University of Transport, Belarus, 246017, Gomel, Krasnaarmeyskaya Str. 4a, 403 E-Mail: belgut@tut.by Received by the editors: 17.05.2004.