Some properties of primitive matrices over Bezout B-domain
The properties of primitive matrices (matrices for which the greatest common divisor of the minors of maximal order is equal to 1) over Bezout B - domain, i.e. commutative domain finitely generated principal ideal in which for all a,b,c with (a,b,c) = 1,c 6= 0, there exists element r ∈ R, such t...
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Cite this: | Some properties of primitive matrices over Bezout B-domain / V.P. Shchedryk // Algebra and Discrete Mathematics. — 2005. — Vol. 4, № 2. — С. 46–57. — Бібліогр.: 14 назв. — англ. |
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irk-123456789-1566262019-06-19T01:29:31Z Some properties of primitive matrices over Bezout B-domain Shchedryk, V.P. The properties of primitive matrices (matrices for which the greatest common divisor of the minors of maximal order is equal to 1) over Bezout B - domain, i.e. commutative domain finitely generated principal ideal in which for all a,b,c with (a,b,c) = 1,c 6= 0, there exists element r ∈ R, such that (a+rb,c) = 1 is investigated. The results obtained enable to describe invariants transforming matrices, i.e. matrices which reduce the given matrix to its canonical diagonal form. 2005 Article Some properties of primitive matrices over Bezout B-domain / V.P. Shchedryk // Algebra and Discrete Mathematics. — 2005. — Vol. 4, № 2. — С. 46–57. — Бібліогр.: 14 назв. — англ. 1726-3255 2000 Mathematics Subject Classification: 15A21. http://dspace.nbuv.gov.ua/handle/123456789/156626 en Algebra and Discrete Mathematics Інститут прикладної математики і механіки НАН України |
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The properties of primitive matrices (matrices
for which the greatest common divisor of the minors of maximal
order is equal to 1) over Bezout B - domain, i.e. commutative
domain finitely generated principal ideal in which for all a,b,c with
(a,b,c) = 1,c 6= 0, there exists element r ∈ R, such that (a+rb,c) =
1 is investigated. The results obtained enable to describe invariants
transforming matrices, i.e. matrices which reduce the given matrix
to its canonical diagonal form. |
format |
Article |
author |
Shchedryk, V.P. |
spellingShingle |
Shchedryk, V.P. Some properties of primitive matrices over Bezout B-domain Algebra and Discrete Mathematics |
author_facet |
Shchedryk, V.P. |
author_sort |
Shchedryk, V.P. |
title |
Some properties of primitive matrices over Bezout B-domain |
title_short |
Some properties of primitive matrices over Bezout B-domain |
title_full |
Some properties of primitive matrices over Bezout B-domain |
title_fullStr |
Some properties of primitive matrices over Bezout B-domain |
title_full_unstemmed |
Some properties of primitive matrices over Bezout B-domain |
title_sort |
some properties of primitive matrices over bezout b-domain |
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Інститут прикладної математики і механіки НАН України |
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2005 |
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http://dspace.nbuv.gov.ua/handle/123456789/156626 |
citation_txt |
Some properties of primitive matrices over Bezout B-domain / V.P. Shchedryk // Algebra and Discrete Mathematics. — 2005. — Vol. 4, № 2. — С. 46–57. — Бібліогр.: 14 назв. — англ. |
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Algebra and Discrete Mathematics |
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AT shchedrykvp somepropertiesofprimitivematricesoverbezoutbdomain |
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2025-07-14T09:00:55Z |
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.
Algebra and Discrete Mathematics RESEARCH ARTICLE
Number 2. (2005). pp. 46 – 57
c© Journal “Algebra and Discrete Mathematics”
Some properties of primitive matrices over
Bezout B-domain
V. P. Shchedryk
Communicated by M.Ya. Komarnytskyj
Abstract. The properties of primitive matrices (matrices
for which the greatest common divisor of the minors of maximal
order is equal to 1) over Bezout B - domain, i.e. commutative
domain finitely generated principal ideal in which for all a, b, c with
(a, b, c) = 1, c 6= 0, there exists element r ∈ R, such that (a+rb, c) =
1 is investigated. The results obtained enable to describe invariants
transforming matrices, i.e. matrices which reduce the given matrix
to its canonical diagonal form.
The notation of elementary divisor ring, as rings over which every ma-
trix admits diagonal reduction were introduced by I. Kaplansky in 1949
[1]. Such concept has appeared rather effective at the decision of many
tasks in different areas of modern algebra. The whole direction in the
theory of rings was formed in which the properties of rings of elementary
divisor are studied, new classes of rings were described which possess the
property of a diagonal reduction [2-5]. With current of time the interest
to such rings has not died away – a lot of publications regularly occur
in mathematical journals [6-9]. One of examples of a class elementary
divisor ring are the Bezout B−rings, i.e. commutative domain of finitely
generated principal ideal in which for all a, b, c with (a, b, c) = 1, c 6= 0,
there exists an element r ∈ R, such that (a+ rb, c) = 1 [10]. This paper
is devoted to study of Bezout B−domain from the point of view of re-
search of properties of their elements, and also to describe the invariants
of transformable matrices, i.e. invertible matrices which the given matrix
reduces to its canonical diagonal form.
2000 Mathematics Subject Classification: 15A21.
Key words and phrases: elementary divisor ring, Bezout B−domain, canonical
diagonal form, transformable matrices, invariants, primitive matrices.
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.V. P. Shchedryk 47
Let R be Bezout B−domain. A matrix is called primitive if the great-
est common divisor of minors of the maximal order is equal to 1. In the
first part of this paper the properties of primitive rows and columns are
studied.
Property 1. If (a1, . . . , an) = 1, an 6= 0, n ≥ 3, then there are elements
u2, . . . , un−1, such that
(a1 + u2a2 + . . .+ un−1an−1, an) = 1.
Proof. Let (a2, . . . , an−1) = γ. Then there are elements v2, . . . , vn−1 ,
such that
v2a2 + . . .+ vn−1an−1 = γ.
Since (a1, γ, an) = 1, there is an element r ∈ R, for which (a1 + rγ, an) =
1. Thus
(a1 + (rv2)a2 + . . .+ (rvn−1)an−1, an) = 1.
Property 2. If (a1, . . . , an) = 1, an 6= 0, n ≥ 3, then there are invertible
matrices of the form
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
a1 v1 v2 . . . vn−2 vn−1
a2 1 0 . . . 0 0
a3 0 1 0 0
. . . . . . . . . . . . . . . . . .
an−1 0 0 1 0
an 0 0 . . . 0 vn
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
= V,
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
un 0 . . . 0 0 un−1
0 1 0 0 un−2
. . . . . . . . . . . . . . . . . .
0 0 1 0 u2
0 0 . . . 0 1 u1
an an−1 . . . a3 a2 a1
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
= U.
Proof. First we shall show, that the elements v1, . . . , vn can be chosen
such that the matrix V will be invertible. By property 1 there are ele-
ments v1, . . . , vn−2 , such that
(a1 − v1a2 − . . .− vn−2an−1, an) = 1.
Since detV = vnγn−1−vn−1an, where γn−1 = a1−v1a2− . . .−vn−2an−1,
and taking into consideration (γn−1, a1) = 1 we can choose elements
vn−1, vn so, that detV = 1. It is similarly shown, that there are u1, . . . , un
for which detU = 1.
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.48 Some properties of primitive matrices over...
Since R is finitely generated principal ideal domain then for all finitely
set of relatively prime elements a1, . . . , an, n ≥ 2, there are elements
u1, . . . , un, such that
u1a1 + . . .+ unan = 1. (1)
Write the elements u1, . . . , un as
∥
∥u1 . . . un
∥
∥ . We shall say that el-
ements of the row
∥
∥u1 . . . un
∥
∥ satisfies equation (1). The following
statement suggests a method of finding of such all rows with elements
which satisfy the equation (1).
Property 3. Let (a1, . . . , an) = 1, n ≥ 2, and A be any invertible matrix
for which
∥
∥a1 . . . an
∥
∥T
is its first column. The set
U = {
∥
∥1 x2 . . . xn
∥
∥A−1|xi ∈ R, i = 2, . . . , n}
consist of all rows with elements which satisfy equation (1).
Proof. Let
∥
∥v1 . . . vn
∥
∥ ∈ U, i.e.
∥
∥v1 . . . vn
∥
∥ =
∥
∥1 x2 . . . xn
∥
∥A−1,
where xi ∈ R, i = 2, . . . , n. Then
∥
∥v1 . . . vn
∥
∥
∥
∥a1 . . . an
∥
∥T
=
∥
∥1 x2 . . . xn
∥
∥A−1
∥
∥a1 . . . an
∥
∥T
=
=
∥
∥1 x2 . . . xn
∥
∥
∥
∥1 0 . . . 0
∥
∥T
= 1.
This means that elements of all rows from U satisfy equation (1).
Let elements of the row
∥
∥u1 . . . un
∥
∥ satisfy equation (1) and A−1 =
‖bij‖
n
1
. Consider the matrix
∥
∥
∥
∥
∥
∥
∥
∥
u1 u2 . . . un
b21 b22 . . . b2n
. . . . . . . . . . . .
bn1 bn2 . . . bnn
∥
∥
∥
∥
∥
∥
∥
∥
= U.
Then
UA =
∥
∥
∥
∥
∥
∥
∥
∥
∥
1 x2 . . . xn
0 1 . . . 0
...
. . .
0 0 . . . 1
∥
∥
∥
∥
∥
∥
∥
∥
∥
.
It follows from this that
∥
∥u1 . . . un
∥
∥ ∈ U. This concludes the proof of
our statement.
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.V. P. Shchedryk 49
Property 4. If (a1, . . . , an) = 1, n ≥ 2, and ε1|ε2| . . . |εk, εi 6= 0, i =
1, . . . , k, 1 ≤ k < n, then
(a1εk, a2εk−1, . . . , akε1, ak+1, . . . , an) = (εk, a2εk−1, . . . , akε1, ak+1, . . . , an) .
Proof. Denote (a1εk, a2εk−1, . . . , akε1, ak+1, . . . , an) = δk. In order to
prove this statement it suffices to show that δk|εk. In the case where
k = 1 we have
δ1 = (a1ε1, a2, . . . , an) = (a1ε1, (a2, . . . , an)) = (ε1, (a2, . . . , an)) .
So δ1|ε1. Hence the results holds for k = 1. Let k ≥ 2 and suppose that
the result is established for m < k. Then
δk = (a1εk, a2εk−1, . . . , akε1, ak+1, . . . , an) =
=
(
ε1
(
a1
εk
ε1
, . . . , ak−1
ε2
ε1
, ak
)
, ak+1, . . . , an
)
.
Since ε2
ε1
| ε3
ε1
| . . . | εk
ε1
we have by the induction hypothesis
(
a1
εk
ε1
, . . . , ak−1
ε2
ε1
, ak, ak+1, . . . , an
)
= d1|
εk
ε1
.
Therefore
δk = d1
ε1
(
a1
εk
ε1
, . . . , ak−1
ε2
ε1
, ak
)
d1
,
(
ak+1
d1
, . . . ,
an
d1
)
=
= d1
(
ε1,
(
ak+1
d1
, . . . ,
an
d1
))
= d1d2,
where d2|ε1. Thus δk = d1d2|
εk
ε1
ε1 = εk.
Property 5. Let (a, b, ϕ) = (a1, b1, ϕ) = 1, aba1b1ϕ 6= 0. If
ab1 ≡ a1b(modϕ),
then
(ax+ b, ϕ) = (a1x+ b1, ϕ)
for all x ∈ R.
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.50 Some properties of primitive matrices over...
Proof. Set (a, ϕ) = α. Then (a, b) = 1. As ab1 − a1b = ϕt, we have α|a1b.
By the property 4 α|a1. Hence, α|(a1, ϕ) = α1. From similar reasons
α1|(a, ϕ) = α. Hence α = α1. As
(a1(ax+ b), ϕ) = (a1ax+ a1b, ϕ) = (a1ax+ (a1b+ ϕt), ϕ) =
= (a1ax+ a1b, ϕ) = (a(a1x+ b1), ϕ),
so (a1
α
(ax+ b),
ϕ
α
)
=
( a
α
(a1x+ b1),
ϕ
α
)
.
Therefore (
ax+ b,
ϕ
α
)
=
(
a1x+ b1,
ϕ
α
)
= δ.
Since α|a and α|a1, and also (α, b) = (α, b1) = 1 then for all elements
x ∈ R the equality
(ax+ b, α) = (a1x+ b1, α) = 1
holds. Hence
δ =
(
ax+ b,
ϕ
α
)
=
(
ax+ b,
ϕ
α
α
)
= (ax+ b, ϕ) .
Similarly δ = (a1x+ b1, ϕ) .
Property 6. Let (a1, . . . , an) = 1, n ≥ 2, and ψ ∈ R be any fixed nonzero
element, which is not unit. Then there are elements u1, . . . , un, which
satisfy the following conditions simultaneously:
a) u1a1 + . . .+ unan = 1;
b) (u1, . . . , ui) = 1, for any fixed 2 ≤ i ≤ n;
c) (ui, ψ) = 1, for any fixed 2 ≤ i ≤ n.
Proof. Consider the invertible matrixA with first column
∥
∥a1 . . . an
∥
∥T
.
Let’s show, that matrix A can be chosen in such a way that the elements
of the matrix A−1 = ‖bij‖
n
1
satisfy b3i = . . . = bni = 0. Indeed, let A1
be any invertible matrix with first column
∥
∥a1 . . . an
∥
∥T
, A−1 =
∥
∥b̄ij
∥
∥n
1
and among elements b̄2i, . . . , b̄ni there is at least one not zero. Then there
is such a matrix D ∈ GLn−1(R), that
D
∥
∥b2i . . . bni
∥
∥T
=
∥
∥γ 0 . . . 0
∥
∥T
.
Thus, the matrix
(
(1 ⊕D)A−1
1
)
−1
= A1(1 ⊕D−1) = A
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.V. P. Shchedryk 51
will be found.
Let the matrix consisting of the first i columns of the matrix A−1 has
the form
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
b11 . . . b1,i−1 b1i
b21 . . . b2,i−1 γ
b31 . . . b3,i−1 0
. . . . . . . . . . . .
bi1 . . . bi,i−1 0
——————————
bi+1,1 . . . bi+1,i−1 0
. . . . . . . . . . . .
bn1 . . . bn,i−1 0
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
=
∥
∥
∥
∥
M
N
∥
∥
∥
∥
.
By property 3 every set of elements u1, . . . , un satisfying condition a) can
be presented as follows:
∥
∥u1 . . . un
∥
∥ =
∥
∥1 x2 . . . xn
∥
∥A−1,
where xi ∈ R, i = 2, . . . , n. In order that the our statement be valid it is
sufficient, that there are elements x2 . . . xn, such that
∥
∥1 x2 . . . xn
∥
∥
∥
∥
∥
∥
M
N
∥
∥
∥
∥
=
∥
∥q1 . . . qi
∥
∥ ,
where (q1, . . . , qi) = (qi, ψ) = 1.
Let γ = 0. Since the matrix
∥
∥
∥
∥
M
N
∥
∥
∥
∥
is primitive, we conclude that
b1i ∈ U(R). Therefore b11, . . . , b1i will be found elements.
Let γ 6= 0 and btj 6= 0, i+1 ≤ t ≤ n, 1 ≤ j ≤ i−1. As (b1i, γ) = 1 then
(b1i, γ, ψbtj) = 1. Therefore there is element l, such that (b1i +γl, ψbtj) =
1. This equality implies
i) (d1i, ψ) = 1; (2)
ii) (d1i, btj) = 1,
where d1i = b1i + γl 6= 0. Then (d1j , btj , d1i) = 1, where d1j = b1j + b2jl.
Therefore, there is m, such that (d1j +btjm, d1i) = 1. Taking into account
equality (2), we are convinced, that elements of the first row of the matrix
∥
∥
∥
∥
∥
∥
∥
∥
1 l 0 . . . 0 m
0 1 0 . . . 0 0
. . . . . . . . . . . . . . . . . .
0 0 0 . . . 0 1
∥
∥
∥
∥
∥
∥
∥
∥
⊕ En−t
∥
∥
∥
∥
M
N
∥
∥
∥
∥
,
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.52 Some properties of primitive matrices over...
where En−t is identity (n − t) × (n − t) matrix, will satisfy to all the
requirements of our statement.
If N = 0, or i = n (in this case matrix N is empty) it follows from
invertibility of a matrix A1, that M ∈ GLi(R). Therefore (b1i, γ) =
1, so (b1i, γ, ψ) = 1. As well as in the previous cases there is r, that
(b1i + γr, ψ) = 1. Hence, the elements of the first row of the matrix
(∥
∥
∥
∥
1 r
0 1
∥
∥
∥
∥
⊕ Ei−2
)
M
also will be found elements. The statement is proved.
By the theorem 5.2 of [1] R is elementary divisor domain. Therefore
for every nonsingular n× n matrix A over R exist invertible matrices P
and Q (further we shall call them as transformable matrices), such that
PAQ = diag(ϕ1, . . . , ϕn) = Φ, ϕi|ϕi+1, i = 1, . . . , n− 1. (3)
Denote PA the set of invertible matrices P , which satisfy equality (3). In
a final part of this paper the properties of set of transformable matrices
PA will be studied. It was shown in papers [11-13], that PA = GΦP ,
where P be any fixed matrix from equality (3), and GΦ is multiplicative
group, which consists of all invertible matrices of the form
∥
∥
∥
∥
∥
∥
∥
∥
h11 h12 . . . h1,n−1 h1n
ϕ2
ϕ1
h21 h22 . . . h2,n−1 h2n
. . . . . . . . . . . . . . .
ϕn
ϕ1
hn1
ϕn
ϕ2
h22 . . . ϕn
ϕn−1
hn,n−1 hnn
∥
∥
∥
∥
∥
∥
∥
∥
.
In [12,14] it is proved that the group GΦ and the set of left trans-
formable matrices PA play the main role in the description of the asso-
ciated matrices, which have the given canonical diagonal form Φ.
Proposition ([12, 14]). Let A = P−1
A ΦQ−1
A , B = P−1
B ΦQ−1
B . The follow-
ing are equivalent:
a) A and B are right associates (B = AU, U ∈ GLn(R));
b) PB = HPA, where H ∈ GΦ;
c) PB = PA.
We apply the obtained results to describe the properties of trans-
formable matrices. Denote
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.V. P. Shchedryk 53
Φ1 = En,Φi = diag
ϕi
ϕ1
, . . . ,
ϕi
ϕi−1
, 1, . . . , 1
︸ ︷︷ ︸
n−i+1
, i = 2, . . . , n.
Definition 1. Let
∥
∥a1 . . . an
∥
∥T
be primitive column and
Φi
∥
∥a1 . . . an
∥
∥T
∼
∥
∥δi 0 . . . 0
∥
∥T
,
i = 1, . . . , n. The column
∥
∥δ1 . . . δn
∥
∥T
is called Φ− rod of the column
∥
∥a1 . . . an
∥
∥T
.
Theorem 1. If H ∈ GΦ, then Φ-rods of columns
∥
∥a1 . . . an
∥
∥T
,
H
∥
∥a1 . . . an
∥
∥T
coincide.
Proof. Since j column of the matrix H has the form
∥
∥
∥h1j . . . hjj
ϕj+1
ϕj
hj+1,j . . . ϕn
ϕj
hnj
∥
∥
∥
T
, 1 ≤ j ≤ n− 1,
then Φihj =
=
∥
∥
∥
ϕi
ϕ1
h1j . . .
ϕi
ϕj−1
hj−1,j
ϕi
ϕj
hjj
ϕi
ϕj
hj+1,j . . .
ϕi
ϕj
hij
ϕi+1
ϕj
hi+1,j . . .
ϕn
ϕj
hnj
∥
∥
∥
T
=
ϕi
ϕj
∥
∥
∥
ϕj
ϕ1
h1j . . .
ϕj
ϕj−1
hj−1,j hjj . . . hij
ϕi+1
ϕi
hi+1,j . . . ϕn
ϕi
hnj
∥
∥
∥
T
.
Hence,
ϕi
ϕj
|Φihj , i = 2, . . . , n, j = 1, . . . , n − 1, i > j. It means that the
equalities
ΦiH = KiΦi, (4)
i = 2, . . . , n, holds. As all the matrices Φi are nonsingular, and the matrix
H is invertible, then from equality (4) follows Ki ∈ GLn(R). Therefore
ΦiH
∥
∥a1 . . . an
∥
∥T
= KiΦi
∥
∥a1 . . . an
∥
∥T
∼
∼ Φi
∥
∥a1 . . . an
∥
∥T
∼
∥
∥δi 0 . . . 0
∥
∥T
,
i = 2, . . . , n. It remains to note that δ1 = 1 which concludes the proof of
the theorem.
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.54 Some properties of primitive matrices over...
Theorem 2. Let
∥
∥δ1 . . . δn
∥
∥T
be Φ-rod of the primitive column
∥
∥a1 . . . an
∥
∥T
. Then there is a matrix H ∈ GΦ for which
H
∥
∥a1 . . . an
∥
∥T
=
∥
∥b δ2 . . . δn
∥
∥T
.
Proof. Property 6 implies that there are elements u1, . . . , un, such that
ϕn
ϕ1
u1a1 + . . .+
ϕn
ϕn−1
un−1an−1 + unan = δn,
where
(
un,
ϕn
ϕ1
)
= 1. Since ϕn
ϕn−1
| ϕn
ϕn−2
| . . . |ϕn
ϕ1
, taking in account the prop-
erty 4
(
ϕn
ϕ1
u1, . . . ,
ϕn
ϕn−1
un−1, un
)
=
(
ϕn
ϕ1
,
ϕn
ϕ2
u2, . . . ,
ϕn
ϕn−1
un−1, un
)
=
=
(
ϕn
ϕ2
u2, . . . ,
ϕn
ϕn−1
un−1,
(
un,
ϕn
ϕ1
))
= 1.
By property 2 we shall complete a primitive row
∥
∥
∥
ϕn
ϕ1
u1 . . . ϕn
ϕn−1
un−1 un
∥
∥
∥
to an invertible matrix Hn in which this row will be last, and other el-
ements of this matrix, which lies under the main diagonal will be zero.
Then Hn ∈ GΦ and
Hn
∥
∥a1 . . . an
∥
∥T
=
∥
∥b1 . . . bn−1 δn
∥
∥T
.
By theorem 1 this column will have again Φ-rod
∥
∥δ1 . . . δn
∥
∥T
. There-
fore
Φn−1Hn
∥
∥a1 . . . an
∥
∥T
∼
∥
∥δn−1 0 . . . 0
∥
∥T
.
Hence, there are elements v1, . . . , vn, such that
ϕn−1
ϕ1
v1b1 + . . .+
ϕn−1
ϕn−2
vn−2bn−2 + vn−1bn−1 + vnδn = δn−1.
Moreover, as it follows from property 6, these elements can be chosen in
such a manner that (v1, . . . , vn−1) = 1 and
(
vn−1,
ϕn−1
ϕ1
)
= 1. Thus we
have
(
ϕn−1
ϕ1
v1, . . . ,
ϕn−1
ϕn−2
vn−2, vn−1
)
= 1.
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.V. P. Shchedryk 55
It means, that in the group GΦ there is a matrix Hn−1 with the following
two last rows:
∥
∥
∥
∥
ϕn−1
ϕ1
v1 . . .
ϕn−1
ϕn−2
vn−2 vn−1 vn
0 . . . 0 0 1
∥
∥
∥
∥
.
Consequently,
Hn−1Hn
∥
∥a1 . . . an
∥
∥T
=
∥
∥d1 . . . dn−2 δn−1 δn
∥
∥T
.
Continuing the described process, on (n-1) step we shall receive the matrix
H = H2 · · ·Hn ∈ GΦ, such that HA =
∥
∥b δ2 . . . δn
∥
∥T
. The theorem
is proved.
Denote
∆i =
(
ϕi
ϕi−1
,
ai
δi−1
, . . . ,
an
δi−1
)
, i = 2, . . . , n. (5)
Theorem 3. Let
∥
∥δ1 . . . δn
∥
∥T
be Φ-rod of the primitive column
∥
∥a1 . . . an
∥
∥T
. Then the elements δi satisfy the following conditions:
a) δi = ∆2 · · ·∆i, i = 2, . . . , n;
b) δi|
ϕi
ϕ1
, i = 2, . . . , n.
Proof. Since δ1 = 1, we obtain from property 4
δ2 =
(
ϕ2
ϕ1
a1, a2, . . . , an
)
= ∆2,
δ3 =
(
ϕ3
ϕ1
a1,
ϕ3
ϕ2
a2, a3, . . . , an
)
=
(
ϕ3
ϕ2
(
ϕ2
ϕ1
, a2
)
, a3, . . . , an
)
=
= δ2
ϕ3
ϕ2
(
ϕ2
ϕ1
, a2
)
δ2
,
a3
δ2
, . . . ,
an
δ2
= ∆2
(
ϕ3
ϕ2
,
a3
δ2
, . . . ,
an
δ2
)
= ∆2∆3.
Having continued on analogy our reasons, we obtain δi = ∆2 · · ·∆i, i =
2, . . . , n.
By (5) ∆i|
ϕi
ϕi−1
, i = 2, . . . , n. Hence
δi = ∆2∆3 · · ·∆i−1∆i|
ϕ2
ϕ1
ϕ3
ϕ2
· · ·
ϕi−1
ϕi−2
ϕi
ϕi−1
=
ϕi
ϕ1
, i = 2, . . . , n.
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.56 Some properties of primitive matrices over...
The following corollary follows from the theorems 2 and 3.
Corollary 1. If
∥
∥δ1 . . . δn
∥
∥T
be Φ-rod of the primitive column
∥
∥a1 . . . an
∥
∥T
, then there is a matrix H ∈ GΦ, such that
H
∥
∥a1 . . . an
∥
∥T
=
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
b
∆2
∆2∆3
. . .
∆2∆3 · · ·∆n
∥
∥
∥
∥
∥
∥
∥
∥
∥
∥
,
where ∆i|
ϕi
ϕi−1
, i = 2, . . . , n.
Definition 2. Let P ∈ GLn(R) and p̄1, . . . , p̄n be its columns,
∥
∥δi1 . . . δin
∥
∥T
is Φ− rod of column p̄i, i = 1, . . . , n. The matrix ‖δij‖
n
1
is called Φ − rod of the matrix P .
Theorem 4. Φ-rods of matrices from PA coincide.
Proof. Let P1 be any matrix from PA. Since PA = GΦP then there exists
a matrix H ∈ GΦ, such that P1 = HP. According to the theorem 1 Φ-
rods correspond columns of matrices P and P1 coincide. Therefore will
be Φ-rods of these matrices coincide.
Since all matrices of the set PA have identical Φ-rods, it is possible to
speak about Φ-rod of set of transformable matrices PA, having identified
it with Φ-rod of any matrix of this set. Using the theorem 2, we obtain.
Corollary 2. Let ‖δij‖
n
1
be Φ-rod of the set PA. Then there is matrix
Pi ∈ PA, which have i column of the form
∥
∥∗ δi1 . . . δin
∥
∥T
, 1 ≤ i ≤ n.
Corollary 3. If the matrices A and B have the canonical diagonal form
Φ and are right associates, then Φ-rods of sets PA and PB coincide.
Proof. By proposition PA = PB, so that Φ-rods of these sets coincide.
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Contact information
V. P. Shchedryk Department of Algebra
Pidsryhach Institute for Applied Problems
of Mechanics and Mathematics
National Academy of Sciences of Ukraine
3b Naukova Str.
Lviv, 79060, UKRAINE
Received by the editors: 11.05.2004
and final form in 08.05.2005.
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