Spectral properties of partial automorphisms of a binary rooted tree

We study asymptotics of the spectral measure of a randomly chosen partial automorphism of a rooted tree. To every partial automorphism x we assign its action matrix Ax. It is shown that the uniform distribution on eigenvalues of Ax converges weakly in probability to δ₀ as n → ∞, where δ₀ is the delt...

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Date:2018
Main Author: Kochubinska, E.
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Language:English
Published: Інститут прикладної математики і механіки НАН України 2018
Series:Algebra and Discrete Mathematics
Online Access:http://dspace.nbuv.gov.ua/handle/123456789/188414
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Cite this:Spectral properties of partial automorphisms of a binary rooted tree / E. Kochubinska // Algebra and Discrete Mathematics. — 2018. — Vol. 26, № 2. — С. 280–289. — Бібліогр.: 6 назв. — англ.

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spelling irk-123456789-1884142023-02-28T01:27:07Z Spectral properties of partial automorphisms of a binary rooted tree Kochubinska, E. We study asymptotics of the spectral measure of a randomly chosen partial automorphism of a rooted tree. To every partial automorphism x we assign its action matrix Ax. It is shown that the uniform distribution on eigenvalues of Ax converges weakly in probability to δ₀ as n → ∞, where δ₀ is the delta measure concentrated at 0. 2018 Article Spectral properties of partial automorphisms of a binary rooted tree / E. Kochubinska // Algebra and Discrete Mathematics. — 2018. — Vol. 26, № 2. — С. 280–289. — Бібліогр.: 6 назв. — англ. 1726-3255 2010 MSC: 20M18, 20M20,05C05. http://dspace.nbuv.gov.ua/handle/123456789/188414 en Algebra and Discrete Mathematics Інститут прикладної математики і механіки НАН України
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
collection DSpace DC
language English
description We study asymptotics of the spectral measure of a randomly chosen partial automorphism of a rooted tree. To every partial automorphism x we assign its action matrix Ax. It is shown that the uniform distribution on eigenvalues of Ax converges weakly in probability to δ₀ as n → ∞, where δ₀ is the delta measure concentrated at 0.
format Article
author Kochubinska, E.
spellingShingle Kochubinska, E.
Spectral properties of partial automorphisms of a binary rooted tree
Algebra and Discrete Mathematics
author_facet Kochubinska, E.
author_sort Kochubinska, E.
title Spectral properties of partial automorphisms of a binary rooted tree
title_short Spectral properties of partial automorphisms of a binary rooted tree
title_full Spectral properties of partial automorphisms of a binary rooted tree
title_fullStr Spectral properties of partial automorphisms of a binary rooted tree
title_full_unstemmed Spectral properties of partial automorphisms of a binary rooted tree
title_sort spectral properties of partial automorphisms of a binary rooted tree
publisher Інститут прикладної математики і механіки НАН України
publishDate 2018
url http://dspace.nbuv.gov.ua/handle/123456789/188414
citation_txt Spectral properties of partial automorphisms of a binary rooted tree / E. Kochubinska // Algebra and Discrete Mathematics. — 2018. — Vol. 26, № 2. — С. 280–289. — Бібліогр.: 6 назв. — англ.
series Algebra and Discrete Mathematics
work_keys_str_mv AT kochubinskae spectralpropertiesofpartialautomorphismsofabinaryrootedtree
first_indexed 2025-07-16T10:26:52Z
last_indexed 2025-07-16T10:26:52Z
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fulltext “adm-n4” — 2019/1/24 — 10:02 — page 280 — #130 Algebra and Discrete Mathematics RESEARCH ARTICLE Volume 26 (2018). Number 2, pp. 280–289 c© Journal “Algebra and Discrete Mathematics” Spectral properties of partial automorphisms of a binary rooted tree Eugenia Kochubinska Communicated by A. P. Petravchuk Abstract. We study asymptotics of the spectral measure of a randomly chosen partial automorphism of a rooted tree. To every partial automorphism x we assign its action matrix Ax. It is shown that the uniform distribution on eigenvalues of Ax converges weakly in probability to δ0 as n → ∞, where δ0 is the delta measure concentrated at 0. Introduction We consider a semigroup of partial automorphisms of a binary n- level rooted tree. Throughout the paper by a partial automorphism we mean root-preserving injective tree homomorphism defined on a connected subtree. This semigroup was studied, in particular, in [4, 5]. We are interested in spectral properties of this semigroup. There is a lot of paper dealing with spectrum of action matrices for the action of finitely generated groups on a regular rooted tree. The exhaustive research on spectra of fractal groups is provided in [1]. The eigenvalues of random wreath product of symmetric group were studied by Evans in [2]; he assigned equal probabilities to the eigenvalues of a randomly chosen automorphism of a regular rooted tree, and considered the random measure Θn on the unit circle C. He has shown that Θn converges weakly 2010 MSC: 20M18, 20M20,05C05. Key words and phrases: partial automorphism, semigroup, eigenvalues, random matrix, delta measure. “adm-n4” — 2019/1/24 — 10:02 — page 281 — #131 E. Kochubinska 281 in probability to λ as n → ∞, where λ is the normalized Lebesgue measure on the unit circle. Let Bn = {vni | i = 1, . . . , 2n} be the set of vertices of the nth level of the n-level binary rooted tree. To a randomly chosen partial automorphism x, we assign the action matrix Ax = ( 1{x(vni )=vnj } )2n i,j=1 . Let Ξn = 1 2n 2n ∑ k=1 δλk be the uniform distribution on eigenvalues of Ax. We show that Ξn converges weakly in probability to δ0 as n → ∞, where δ0 is the delta measure concentrated at 0. This result can be generalized to a regular rooted tree, however, this generalization is not straightforward and will be studied elsewhere. The remaining of the paper is organized as follows. Section 2 contains basic facts on a partial wreath product of semigroup and its connection with a semigroup of partial automorphisms of a regular rooted tree. The main result is stated and proved in Section 3. 1. Preliminaries For a set X = {1, 2} consider the set I2 of all partial bijections. List all of them using standard tableax representation: {( 1 2 1 2 ) , ( 1 2 2 1 ) , ( 1 2 1 ∅ ) , ( 1 2 ∅ 2 ) , ( 1 2 2 ∅ ) , ( 1 2 ∅ 1 ) , ( 1 2 ∅ ∅ )} . This set forms an inverse semigroup under natural composition law, namely, f ◦ g : dom(f)∩ f−1 dom(g) ∋ x 7→ g(f(x)) for f, g ∈ I2. Obviously, I2 is a particular case of the well-known inverse symmetric semigroup. Detailed description of it can be found in [3, Chapter 2]. Recall the definition of a partial wreath product of semigroups. Let S be an arbitrary semigroup. For functions f : dom(f) → S, g : dom(g) → S define the product fg as: dom(fg) = dom(f) ∩ dom(g), (fg)(x) = f(x)g(x) for all x ∈ dom(fg). For a ∈ I2, f : dom(f) → S, define fa as: (fa)(x) = f(xa), dom(fa) = {x ∈ dom(a);xa ∈ dom(f)}. “adm-n4” — 2019/1/24 — 10:02 — page 282 — #132 282 Spectral properties of partial automorphisms Definition 1. The partial wreath square of the semigroup I2 is the set {(f, a) | a ∈ I2, f : dom(a) → I2} with composition defined by (f, a) · (g, b) = (fga, ab) Denote it by I2 ≀p I2. The partial wreath square of I2 is a semigroup, moreover, it is an inverse semigroup [6, Lemmas 2.22 and 4.6]. We may recursively define any partial wreath power of the finite inverse symmetric semigroup. Denote by Pn the nth partial wreath power of I2. Definition 2. The partial wreath n-th power of semigroup I2 is defined as a semigroup Pn = ( Pn−1 ) ≀p I2 = {(f, a) | a ∈ I2, f : dom(a) → Pn−1} with composition defined by (f, a) · (g, b) = (fga, ab), where Pn−1 is the partial wreath (n− 1)-th power of semigroup I2 Proposition 1. Let Nn be the number of elements in the semigroup Pn. Then Nn = 22 n+1−1 − 1 Proof. We proceed by induction. If n = 1, then 22 2−1 − 1 = 7. This is exactly the number of elements in I2. Assume that Nn−1 = 22 n−1 − 1. Then Nn = |{(f, a) | a ∈ I2, f : dom(a) → Nn−1}| = ∑ a∈I2 N |dom(a)| n−1 = ∑ a∈I2 ( 22 n−1 − 1 )|dom(a)| = 1 + 4 · (22 n−1 − 1) + 2 · (22 n−1 − 1)2 = 1 + 4 · 22 n−1 − 4 + 2 · 22 n+1−2 − 4 · 22 n−1 + 2 = 22 n+1 − 1. Remark 1. Let T be an n-level binary rooted tree. We define a partial automorphism of a tree T as an isomorphism x : Γ1 → Γ2 of subtrees Γ1 and Γ2 of T containing a root. Denote dom(x) := Γ1, ran(x) := Γ2 domain and image of x respectively. Let PAutT be the set of all partial automorphisms of T . Obviously, PAutT forms a semigroup under natural composition law. It was proved in [4, Theorem 1] that the partial wreath power Pn is isomorphic to PAutT . “adm-n4” — 2019/1/24 — 10:02 — page 283 — #133 E. Kochubinska 283 2. Asymptotic behaviour of a spectral measure of a binary rooted tree We identify x ∈ Pn with a partial automorphism from PAutT . Recall, that Bn denotes the set of vertices of the nth level of T . Clearly, |Bn| = 2n. Let us enumerate the vertices of Bn by positive integers from 1 to 2n: Bn = {vni | i = 1, . . . , 2n} . To a randomly chosen transformation x ∈ Pn, we assign the matrix Ax = ( 1{x(vni )=vnj } )2n i,j=1 . In other words, (i, j)th entry of Ax is equal to 1, if a transformation x maps vni to vnj , and 0, otherwise. Remark 2. In an automorphism group of a tree such a matrix describes completely the action of an automorphism. Unfortunately, for a semigroup this is not the case. Example 1. Consider the partial automorphism x ∈ P2, which acts in the following way v01 v11 v12 v21 v22 v23 v24 //oo (dotted lines mean that these edges are not in domain of x). Then the corresponding matrix for x is Ax =     0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0     . “adm-n4” — 2019/1/24 — 10:02 — page 284 — #134 284 Spectral properties of partial automorphisms Note that if v12 were not in the dom(x) with action on other vertices preserved, then the corresponding matrix would be the same. Let χx(λ) be the characteristic polynomial of Ax and λ1, . . . , λ2n be its roots respecting multiplicity. Denote Ξn = 1 2n 2n ∑ k=1 δλk the uniform distribution on eigenvalues of Ax. Theorem 1. For any function f ∈ C(D), where D = {z ∈ C | |z| 6 1} is a unit disc, ∫ D f(x) Ξn(dx) P −→ f(0), n → ∞. (1) In other words, Ξn converges weakly in probability to δ0 as n → ∞, where δ0 is the delta-measure concentrated at 0. Remark 3. Evans [2] has studied asymptotic behaviour of a spectral measure of a randomly chosen element σ of n-fold wreath product of the symmetric group Sd. He considered the random measure Θn on the unit circle C, assigning equal probabilities to the eigenvalues of σ. Evans has shown that if f is a trigonometric polynomial, then lim n→∞ P {∫ C f(x)Θn(dx) 6= ∫ f(x)λ(dx) } = 0, where λ is the normalized Lebesgue measure on the unit circle. Conse- quently, Θn converges weakly in probability to λ as n → ∞. In fact, Theorem 1 speaks about the number of non-zero roots of characteristic polynomial χx(λ). Let us find an alternative description for them. Denote Sn(x) = ⋂ m>1 dom(xm) = { vnj | vnj ∈ dom(xm) for all m > 1 } the vertices of the nth level, which “survive” under the action of x, and define the ultimate rank of x by rkn(x) = |Sn(x)|. Let Rn denote the total number of these vertices over all x ∈ Pn, that is Rn = ∑ x∈Pn rkn(x). We call the number Rn the total ultimate rank. “adm-n4” — 2019/1/24 — 10:02 — page 285 — #135 E. Kochubinska 285 Lemma 1. For x ∈ Pn the number of non-zero roots of χx with regard for multiplicity is equal to the ultimate rank rkn(x) of x. Proof. Let x ∈ Pn and Ax be its action matrix. Consider Ax as a matrix in a standard basis. Let w be some basis vector. It follows from the definition of Ax that there are two possibilities: if the vertex v corresponding to w is in domain of x, then Ax sends w to another basis vector, otherwise, to the zero vector. Since x is a partial bijection, applying Ax repeatedly, we can either get the same vector or the zero vector; An xw = 0 means that v /∈ domxn. In the first case, the vector w corresponds to a non-zero root of χx (some root of unity), and the vertex v contributes to the ultimate rank. In the second case, the vector is a root vector for the zero eigenvalue, so it corresponds to a zero root of Ax, while the corresponding vector does not contribute to the ultimate rank. Denote rankn(x) = | dom(x) ∩Bn| and define the total rank R′ n = ∑ x∈Pn rankn(x). Remark 4. Clearly, for x = (f, a), where a ∈ I2, f : dom(a) → Pn−1, rankn(x) = ∑ y∈dom(a) rankn−1(f(y)) (2) if dom(a) 6= ∅ and rankn(x) = 0 otherwise. Lemma 2. Let R′ n be the total rank of the semigroup Pn. Then R′ n = 4R′ n−1 + 4R′ n−1Nn−1. Proof. Thanks to (2), R′ n = ∑ x=(f,a)∈Pn rankn(x) = ∑ x=(f,a)∈Pn ∑ y∈dom(a) rankn−1(f(y)) = ∑ a∈I2 |dom(a)|=1 ∑ f1∈Pn−1 rankn−1(f1) + ∑ a∈I2 |dom(a)|=2 ∑ f1,f2∈Pn−1 (rankn−1(f1) + rankn−1(f2)) = 4R′ n−1 + 2 ∑ f1,f2∈Pn−1 (rankn−1(f1) + rankn−1(f2)) . “adm-n4” — 2019/1/24 — 10:02 — page 286 — #136 286 Spectral properties of partial automorphisms We have ∑ f1,f2∈Pn−1 rankn−1(f1) = ∑ f1∈Pn−1 ∑ f2∈Pn−1 rank(f1) = ∑ f1∈Pn−1 Nn−1 rank(f1) = Nn−1R ′ n−1. Hence, by symmetry, R′ n = 4R′ n−1 + 4R′ n−1Nn−1. Lemma 3. Let R′ n be the total rank of the semigroup Pn. Then R′ n = 2n−1(1 +Nn) = 22 n+n−2. Proof. We proceed by induction. A direct calculation gives R′ 1 = 8 = 1 +N1. Assuming that R′ n−1 = 22 n−1+n−3, we have, thanks to Lemma 2 and Proposition 1, R′ n = 4R′ n−1(1 +Nn−1) = 4 · 22 n−1+n−3 · 22 n−1−1 = 22 n+n−2, as required. Lemma 4. Let Rn be the total ultimate rank of the semigroup Pn. Then Rn 6 3Rn−1 + 3Rn−1Nn−1. Proof. Represent Rn as a sum Rn = ∑ x=(f,a)∈Pn rkn(x) = ∑ x=(f,a)∈Pn |dom(a)|=1 rkn(x) + ∑ x=(f,a)∈Pn |dom(a)|=2 rkn(x). If rank(a) = 1, then we will be interested only in those a for which a = (1) and a = (2), since otherwise the ultimate rank of x is 0. Therefore, ∑ x=(f,a)∈Pn | dom(a)|=1 rkn(x) = ∑ a∈{(1),(2)} ∑ f1∈Pn−1 rkn−1(f1) = 2 ∑ f1∈Pn−1 rkn−1(f1) = 2Rn−1. “adm-n4” — 2019/1/24 — 10:02 — page 287 — #137 E. Kochubinska 287 If rank(a) = 2, then ∑ x=(f,a)∈Pn | dom(a)|=2 rkn(x) = ∑ x=(f,a)∈Pn a=(1)(2) rkn(x) + ∑ x=(f,a)∈Pn a=(12) rkn(x) =: S1 + S2. Clearly, if x = (f, a) with a = (1)(2), then rkn(x) = rkn−1(f(1)) + rkn−1(f(2)), whence S1 = ∑ f1,f2∈Pn−1 (rkn−1(f1) + rkn−1(f2)) = 2 ∑ f1,f2∈Pn−1 rkn−1(f1) = 2Rn−1Nn−1. Further, if x = (f, a) with a = (12), then rkn(x) = 2 rkn−1(f(1)(f(2)). So, S2 = 2 ∑ f1,f2∈Pn−1 rkn−1(f1f2). Note that every element x ∈ Pn can be represented as a product x = eσ, where e is an idempotent on dom(x) and σ is a permutation on the set of the tree vertices. Then ∑ x2∈Pn−1 rkn−1(x1x2) = ∑ x2∈Pn−1 rkn−1(eσx2) = ∑ x2∈Pn−1 rkn−1(ex2). The last equality is true since transformation x 7→ σx is bijective on Pn−1. It follows from above that S2 = 2 ∑ f1,f2∈Pn−1 rkn−1(f1f2) = 2 ∑ f1∈Pn−1 ∑ f2∈Pn−1 rkn−1(iddom(f1) f2) 6 2 ∑ f1∈Pn−1 ∑ f2∈Pn−1 |dom(f1) ∩ Sn−1(f2)| = 2 ∑ f1∈Pn−1 ∑ f2∈Pn−1 2n−1 ∑ j=1 1{vn−1 j ∈dom(f1)} · 1{vn−1 j ∈Sn−1(f2)} = 2 2n−1 ∑ j=1 ∑ f1∈Pn−1 1{vn−1 j ∈dom(f1)} · ∑ f2∈Pn−1 1{vn−1 j ∈Sn−1(f2)} . “adm-n4” — 2019/1/24 — 10:02 — page 288 — #138 288 Spectral properties of partial automorphisms Thanks to symmetry, for each j, we have ∑ x∈Pn 1{vn−1 j ∈dom(x)} = ∑ x∈Pn 1{vn−1 1 ∈dom(x)}. Therefore, 1 2n ∑ x∈Pn 2n−1 ∑ k=1 1{vn−1 k ∈dom(x)} = 1 2n−1 |dom(x)| . Thus, we can write S2 = 2 2n−1 ∑ j=1 ∑ f1∈Pn−1 1 2n−1 |dom(f1)|1{vn−1 j ∈Sn−1(f2)} = 1 2n−1 ∑ f1∈Pn |dom(f1)| 2n ∑ j=1 1{vn−1 j ∈Sn−1(f2)} = 2 · 1 2n−1 ∑ f1∈Pn−1 |dom(f1)| · ∑ f2∈Pn−1 |Sn−1(f2)| . Using that |Sn−1(f2)| = rkn−1(f2), |dom(f1)| = rank(f1), and applying Lemma 3, we get 2 2n−1 Rn−1R ′ n−1 = 2Rn−1 · (1 +Nn−1)2 n−2 2n−1 = 2Rn−1(1 +Nn−1) 2 = (1 +Nn−1)Rn−1. Therefore, Rn 6 2Rn−1+2Rn−1Nn−1+(1+Nn−1)Rn−1 = 3Rn−1+3Rn−1Nn−1. Lemma 5. Let pn = Rn 2nNn for n ∈ N. Then pn 6 3 4 pn−1, n > 2. Proof. Using Lemma 4, we get pn = Rn 2nNn 6 3Rn−1 + 3Rn−1Nn−1 2nNn = 3Rn−1(1 +Nn−1) 2nNn = 3Rn−1 · 2 2n−1 2n(22n+1−1 − 1) = 3 2 · Rn−1 2n−1(22n − 21−2n) 6 3 2 · Rn−1 2n−1(22n − 2) = 3 2 · Rn−1 2n(22n−1 − 1) = 3 4 · Rn−1 2n−1Nn−1 = 3 4 · pn−1. “adm-n4” — 2019/1/24 — 10:02 — page 289 — #139 E. Kochubinska 289 Proof of Theorem 1. Note that ∫ D f(z)Ξn(dz) = 1 2n ∑2n k=1 f(λk), where λ1, . . . , λ2n are the roots of the characteristic polynomial χx(λ). Then, thanks to Lemma 1, ∣ ∣ ∣ ∣ ∫ D f(z)Ξn(dz)− f(0) ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ ∫ D (f(z)− f(0)) Ξ(dz) ∣ ∣ ∣ ∣ 6 1 2n ∑ k:λk 6=0 |(f(k)− f(0))| 6 2max D |f | · |k : λk 6= 0| 2n = 2max D |f | rkn(x) 2n . Therefore, E ∣ ∣ ∣ ∣ ∫ D f(z)Ξ(dz)− f(0) ∣ ∣ ∣ ∣ 6 2max |f | · ∑ z∈Pn rkn(x) 2nNn = 2max |f | · pn, where pn is defined in Lemma 5. By Lemma 5, pn 6 3 4 · pn−1 6 . . . 6 (34) n−1p0, whence pn → 0, n → ∞. Consequently, E ∣ ∣ ∫ D f(z)Ξ(dz)− f(0) ∣ ∣ → 0, n → ∞, whence the state- ment follows. Remark 5. We can see from the proof that the rate of convergence in (1) is in some sense exponential. References [1] Bartholdi L., Grigorchuk R. On the Hecke type operators related to some fractal groups, Proc. Steklov Inst. Math. 231, 2000, pp. 1-41. [2] Evans S.N. Eigenvaluse of random wreath products, Electron. J. Probability. Vol.7, No. 9, 2002, pp. 1-15. [3] Ganyushkin O., Mazorchuk V. Classical Finite Transformation Semigroups. An Introduction, Springer, 2008. [4] Kochubinska E. Combinatorics of partial wreath power of finite inverse symmetric semigroup ISd, Algebra discrete math., 2007, N.1, pp. 49-61. [5] Kochubinska E.On cross-sections of partial wreath product of inverse semigroups, Electron. Notes Discrete Math., Vol.28, 2007, pp. 379-386. [6] Meldrum J.D.P. Wreath product of groups and semigroups, Pitman Monographs and Surveys in Pure and Applied Mathematics, 74. Harlow: Longman Group Ltd. 1995. Contact information E. Kochubinska Taras Shevchenko National University of Kyiv, Volodymyrska, 64, 01601, Kiev, Ukraine E-Mail(s): eugenia@univ.kiev.ua Received by the editors: 29.08.2017 and in final form 17.12.2017.