Additivity of elementary maps on alternative rings

Let ℜ and ℜ′ be alternative rings. In this article we investigate the additivity of surjective elementary maps of ℜ × ℜ′. As a main theorem, we prove that if ℜ idempotent satisfying some conditions, these maps are additive.

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Zitieren:Additivity of elementary maps on alternative rings / B.L.M. Ferreira // Algebra and Discrete Mathematics. — 2019. — Vol. 28, № 1. — С. 94–106. — Бібліогр.: 7 назв. — англ.

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spelling irk-123456789-1884792023-03-03T01:26:53Z Additivity of elementary maps on alternative rings Ferreira, B.L.M. Let ℜ and ℜ′ be alternative rings. In this article we investigate the additivity of surjective elementary maps of ℜ × ℜ′. As a main theorem, we prove that if ℜ idempotent satisfying some conditions, these maps are additive. 2019 Article Additivity of elementary maps on alternative rings / B.L.M. Ferreira // Algebra and Discrete Mathematics. — 2019. — Vol. 28, № 1. — С. 94–106. — Бібліогр.: 7 назв. — англ. 1726-3255 2010 MSC: 17A36, 17D99 http://dspace.nbuv.gov.ua/handle/123456789/188479 en Algebra and Discrete Mathematics Інститут прикладної математики і механіки НАН України
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
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description Let ℜ and ℜ′ be alternative rings. In this article we investigate the additivity of surjective elementary maps of ℜ × ℜ′. As a main theorem, we prove that if ℜ idempotent satisfying some conditions, these maps are additive.
format Article
author Ferreira, B.L.M.
spellingShingle Ferreira, B.L.M.
Additivity of elementary maps on alternative rings
Algebra and Discrete Mathematics
author_facet Ferreira, B.L.M.
author_sort Ferreira, B.L.M.
title Additivity of elementary maps on alternative rings
title_short Additivity of elementary maps on alternative rings
title_full Additivity of elementary maps on alternative rings
title_fullStr Additivity of elementary maps on alternative rings
title_full_unstemmed Additivity of elementary maps on alternative rings
title_sort additivity of elementary maps on alternative rings
publisher Інститут прикладної математики і механіки НАН України
publishDate 2019
url http://dspace.nbuv.gov.ua/handle/123456789/188479
citation_txt Additivity of elementary maps on alternative rings / B.L.M. Ferreira // Algebra and Discrete Mathematics. — 2019. — Vol. 28, № 1. — С. 94–106. — Бібліогр.: 7 назв. — англ.
series Algebra and Discrete Mathematics
work_keys_str_mv AT ferreirablm additivityofelementarymapsonalternativerings
first_indexed 2025-07-16T10:33:15Z
last_indexed 2025-07-16T10:33:15Z
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fulltext “adm-n3” — 2019/10/20 — 9:35 — page 94 — #96 Algebra and Discrete Mathematics RESEARCH ARTICLE Volume 28 (2019). Number 1, pp. 94–106 c© Journal “Algebra and Discrete Mathematics” Additivity of elementary maps on alternative rings B. L. M. Ferreira Communicated by I. P. Shestakov Abstract. Let R and R ′ be alternative rings. In this arti- cle we investigate the additivity of surjective elementary maps of R×R ′. As a main theorem, we prove that if R contains a non-trivial idempotent satisfying some conditions, these maps are additive. 1. Alternative rings and elementary maps Let R be a ring not necessarily associative or commutative and consider the following convention for its multiplication operation: xy · z = (xy)z and x · yz = x(yz) for x, y, z ∈ R, in order to reduce the number of parentheses. We denote the associator of R by (x, y, z) = xy · z − x · yz for x, y, z ∈ R. Let X = {xi}i∈N be an arbitrary set of variables. A non-associative monomial of degree 1 is any element of X. Given a natural number n > 1, a non-associative monomial of degree n is an expression of the form (u)(v), where u is a non-associative monomial of some degree i and v is a non- associative monomial of degree n− i. A non-associative polynomial f over a ring R is any formal linear combination of non-associative monomials with coefficients in R. If f includes no variables except x1, x2, . . . , xn and a1, a2, . . . , an is a set of elements of R, then f(a1, a2, . . . , an) is an element of R which results by applying the sequence of operations forming f to a1, a2, . . . , an in place of x1, x2, . . . , xn. 2010 MSC: 17A36, 17D99. Key words and phrases: elementary maps, alternative rings, additivity. “adm-n3” — 2019/10/20 — 9:35 — page 95 — #97 B. L. M. Ferreira 95 Let R and R ′ be two rings and let M : R → R ′ and M∗ : R′ → R be two maps. We call the ordered pair (M,M∗) an elementary map of R×R ′ if for all non-associative monomial f = f(x1, x2, x3) of degree 3 M ( f ( a,M∗(x), b )) = f ( M(a), x,M(b) ) , M∗ ( f ( x,M(a), y )) = f ( M∗(x), a,M∗(y) ) for all a, b ∈ R and x, y ∈ R ′. We say that the elementary map (M,M∗) of R×R ′ is additive (resp., injective, surjective, bijective) if both maps M and M∗ are additive (resp., injective, surjective, bijective). A ring R is said to be alternative if (x, x, y) = 0 = (y, x, x) for all x, y ∈ R. It is easily seen that any associative ring is an alternative ring. An alternative ring R is called k-torsion free if k x = 0 implies x = 0, for any x ∈ R, where k ∈ Z, k > 0, and prime if AB 6= 0 for any two nonzero ideals A,B ⊆ R. Let us consider R an alternative ring and fix a non-trivial idempotent e1 ∈ R, i.e, e2 1 = e1, e1 6= 0 and e1 is not a unity element. Let e2 : R → R and e′ 2 : R → R be linear operators given by e2(a) = a− e1a and e′ 2 (a) = a−ae1. Clearly e2 2 = e2, (e ′ 2 )2 = e′ 2 and we note that if R has a unity, then we can consider e2 = 1 − e1 ∈ R. Let us denote e2(a) by e2a and e′ 2 (a) by ae2. It is easy to see that eia · ej = ei · aej (i, j = 1, 2) for all a ∈ R. Then R has a Peirce decomposition R = R11 ⊕R12 ⊕R21 ⊕R22, where Rij = eiRej (i, j = 1, 2), (see [3]) satisfying the multiplicative relations: (i) RijRjl ⊆ Ril (i, j, l = 1, 2); (ii) RijRij ⊆ Rji (i, j = 1, 2); (iii) RijRkl = 0, if j 6= k and (i, j) 6= (k, l), (i, j, k, l = 1, 2); (iv) x2ij = 0, for all xij ∈ Rij (i, j = 1, 2; i 6= j). According to [4], “The first surprising result on how the multiplicative structure of a ring determines its additive structure is due to Martindale III (1969). In Martindale III (1969, [5] Theorem), he established a condition on a ring R such that every multiplicative bijective map on R is additive." Li and Lu [4] also considered this question in the context of associative rings containing a non-trivial idempotent. They proved the following theorem. Theorem 1. [4, Li and Lu] Let R and R ′ be two associative rings. Sup- pose that R is a 2-torsion free ring containing a family {eα|α ∈ Λ} of idempotents which satisfies: (i) If x ∈ R is such that xR = 0, then x = 0; “adm-n3” — 2019/10/20 — 9:35 — page 96 — #98 96 Additivity of elementary maps on alternative rings (ii) If x ∈ R is such that eαRx = 0 for all α ∈ Λ, then x = 0 (and hence Rx = 0 implies x = 0); (iii) For each α ∈ Λ and x ∈ R, if eαxeαR(1− eα) = 0 then eαxeα = 0. Then every surjective elementary map (M,M∗) of R×R ′ is additive. The hypotheses in Li and Lu’s Theorem [4] allowed the author to make its proof based on calculus using Peirce decomposition notion for associative rings. The notion of Peirce decomposition for alternative rings is similar to that one for associative rings. However, this similarity is restricted to its written form, not including its theoretical structure since Peirce decomposition for alternative rings is a generalization of that classical one for associative rings. Taking this fact into account, in the present paper we generalize the main Li and Lu’s Theorem [4] to the class of alternative rings. For this purpose, we adopt and follow the same structure of the proof proposed by [4], in order to preserve the author’s ideas and to highlight the generalization of associative results to the alternative results. Therefore, our lemmas and the main theorem, which seem to be equal in written form to those presented in lemmas and the theorem proposed in Li and Lu [4], are distinguished by a fundamental item: the use of the non-associative multiplications. The symbol “ ·”, as defined in the introduction section of this article, is essential to elucidate how the non-associative multiplication should be done, and also the symbol “·” is used to simplify the notation. Therefore, the symbol “ ·” is crucial to the logic, characterization and generalization of associative results to alternative results. 2. The main result Our main result reads as follows. Theorem 2. Let R and R ′ be two alternative rings. Suppose that R is a 2-torsion free ring containing a family {eα|α ∈ Λ} of idempotents which satisfies: (i) If x ∈ R is such that xR = 0, then x = 0; (ii) If x ∈ R is such that eαR · x = 0 (or eα ·Rx = 0) for all α ∈ Λ, then x = 0 (and hence Rx = 0 implies x = 0); (iii) For each α ∈ Λ and x ∈ R, if (eαxeα)·R(1−eα) = 0 then eαxeα = 0. Then every surjective elementary map (M,M∗) of R×R ′ is additive. “adm-n3” — 2019/10/20 — 9:35 — page 97 — #99 B. L. M. Ferreira 97 For proving Theorem 2 some preparatory material is needed, following same steps as [4]. Firstly, we consider the case when the monomial is of type f = f(x1, x2, x3). We begin with the following lemma. Lemma 1. M(0) = 0 and M∗(0) = 0. Proof. M(0) = M ( 0M∗(0) · 0 ) = M(0)0 ·M(0) = 0. Similarly, we have M∗(0) = 0. Lemma 2. M and M∗ are bijective. Proof. It suffices to prove that M and M∗ are injective. We first show that M is injective. Let x1 and x2 be in R and suppose that M(x1) = M(x2). Since M∗ ( uM(xi) · v ) = M∗(u)xi · M ∗(v) (i = 1, 2) for all u, v ∈ R ′, it follows that M∗(u)x1 · M∗(v) = M∗(u)x2 · M∗(v). Hence from the surjectivity of M∗ and conditions (i) and (ii) we conclude that x1 = x2. Now we turn to proving the injectivity of M∗. Let u1 and u2 be in R ′ and suppose M∗(u1) = M∗(u2). Since M∗M ( xM∗(ui) · y ) = M∗ ( M(x)ui ·M(y) ) = M∗ ( M(x)MM−1(ui) ·M(y) ) = M∗M(x)M−1(ui) ·M ∗M(y) for all x, y ∈ R, it follows that M∗M(x)M−1(u1) ·M ∗M(y) = M∗M(x)M−1(u2) ·M ∗M(y). Noting that M∗M is also surjective, we see that M−1(u1) = M−1(u2), by conditions (i) and (ii). Consequently u1 = u2. Lemma 3. The pair (M∗−1,M−1) is an elementary map of R×R ′, that is, the maps M∗−1 : R → R ′ and M−1 : R′ → R satisfy M∗−1 ( aM−1(x) · b ) = M∗−1(a)x ·M∗−1(b), M−1 ( xM∗−1(a) · y ) = M−1(x)a ·M−1(y) for all a, b ∈ R and x, y ∈ R ′. Proof. The first equality can be obtained from M∗ ( M∗−1(a)x ·M∗−1(b) ) = M∗ ( M∗−1(a)MM−1(x) ·M∗−1(b) ) = aM−1(x) · b and the second one follows in a similar way. “adm-n3” — 2019/10/20 — 9:35 — page 98 — #100 98 Additivity of elementary maps on alternative rings Lemma 4. Let s, a, b ∈ R such that M(s) = M(a) +M(b). Then (i) M(sx · y) = M(ax · y) +M(bx · y) for x, y ∈ R; (ii) M(xy · s) = M(xy · a) +M(xy · b) for x, y ∈ R; (iii) M∗−1(xs·y) = M∗−1(xa·y)+M∗−1(xb·y) for x, y ∈ R for x, y ∈ R; (iv) M(s · xy) = M(a · xy) +M(b · xy) for x, y ∈ R; (v) M(x · ys) = M(x · ya) +M(x · yb) for x, y ∈ R; (vi) M∗−1(x·sy) = M∗−1(x·ay)+M∗−1(x·by) for x, y ∈ R for x, y ∈ R. Proof. (i) Let x, y ∈ R. Then M(sx · y) = M ( sM∗M∗−1(x) · y ) = M(s)M∗−1(x) ·M(y) = ( M(a) +M(b) ) M∗−1(x) ·M(y) = M(a)M∗−1(x) ·M(y) +M(b)M∗−1(x) ·M(y) = M(ax · y) +M(bx · y). (ii) Let x, y ∈ R. Then M(xy · s) = M ( xM∗M∗−1(y) · s ) = M(x)M∗−1(y) ·M(s) = M(x)M∗−1(y) · ( M(a) +M(b) ) = M(x)M∗−1(y) ·M(a) +M(x)M∗−1(y) ·M(b) = M(xy · a) +M(xy · b). (iii) Let x, y ∈ R. By Lemma 2.3 M∗−1(xs · y) = M∗−1(xM−1M(s) · y) = M∗−1(x)M(s) ·M∗−1(y) = M∗−1(x) ( M(a) +M(b) ) ·M∗−1(y) = M∗−1(x)M(a) ·M∗−1(y) +M∗−1(x)M(b) ·M∗−1(y) = M∗−1(xa · y) +M∗−1(xb · y). Similarly, we prove (iv), (v) and (vi), which finishes the proof. Lemma 5. The following statements are true: (i) M(a11 + a12) = M(a11) +M(a12); (ii) M∗−1(a11 + a12) = M∗−1(a11) +M∗−1(a12). “adm-n3” — 2019/10/20 — 9:35 — page 99 — #101 B. L. M. Ferreira 99 Proof. By surjectivity of M , there exists s ∈ R such that M(s) = M(a11)+ M(a12). Now, M(e1e1 · s) = M(e1e1 · a11) +M(e1e1 · a12) = M(s). It follows that e1e1 · s = s which implies s21 = s22 = 0. Also M(s · e1e1) = M(a11 · e1e1) +M(a12 · e1e1) = M(a11). From this equality we get s · e1e1 = a11 and therefore s11 = a11. For an arbitrary b12 ∈ R12, we obtain M(sb12 · e1) = M(a11b12 · e1) +M(a12b12 · e1) = M(a12b12 · e1), which implies sb12 · e1 = a12b12 · e1, or still (s12 − a12)b12 = 0. In a similar way, for an arbitrary b21 ∈ R21, we have M(sb21 · e1) = M(a11b21 · e1) +M(a12b21 · e1) = M(a12b21 · e1). Hence sb21 · e1 = a12b21 · e1 and thus (s12 − a12)b21 = 0. Finally, for b22 ∈ R22, M∗−1(e1s · b22) = M∗−1(e1a11 · b22) +M∗−1(e1a12 · b22) = M∗−1(e1a12 · b22). As a consequence, e1s · b22 = e1a12 · b22 which implies (s12 − a12)b22 = 0. From these considerations, (s12 − a12)R = 0. According to (i), s12 = a12. Similarly, we prove the lemma below. Lemma 6. The following statements are true: (i) M(a11 + a21) = M(a11) +M(a21); (ii) M∗−1(a11 + a21) = M∗−1(a11) +M∗−1(a21). Lemma 7. The following statements are true: (i) M(a11 + a12 + a21 + a22) = M(a11) +M(a12) +M(a21) +M(a22); (ii) M∗−1(a11+a12+a21+a22) = M∗−1(a11)+M∗−1(a12)+M∗−1(a21)+ M∗−1(a22). Proof. By surjectivity of M , there exists s ∈ R such that M(s) = M(a11)+ M(a12) +M(a21) +M(a22). Now, M(e1e1 · s) = M(e1e1 · a11) +M(e1e1 · a12) = M(a11 + a12). “adm-n3” — 2019/10/20 — 9:35 — page 100 — #102 100 Additivity of elementary maps on alternative rings It follows from this equality that e1e1 ·s = a11+a12 which implies s11 = a11 and s12 = s12. Also M(s · e1e1) = M(a11 · e1e1) +M(a21 · e1e1) = M(a11 + a21), from where we get s · e1e1 = a11 + a21, or still s21 = a21. For arbitrary b22, c22 ∈ R22, we have M∗−1(b22s · c22) = M∗−1(b22a11 · c22) +M∗−1(b22a12 · c22) +M∗−1(b22a21 · c22) +M∗−1(b22a22 · c22) = M∗−1(b22a22 · c22). Hence b22s · c22 = b22a22 · c22 which implies b22(s22 − a22) · c22 = 0. Now, for an arbitrary c21 ∈ R21, we have M∗−1(b22s · c21) = M∗−1(b22a11 · c21) +M∗−1(b22a12 · c21) +M∗−1(b22a21 · c21) +M∗−1(b22a22 · c21) = M∗−1(b22a21 · c21 + b22a22 · c21). Thus b22s·c21 = b22a21 ·c21+b22a22 ·c21 and therefore b22(s22−a22)·c21 = 0. As a consequence it follows that b22(s22 − a22) · R = 0 which implies b22(s22 − a22) = 0. Finally, for an arbitrary b12 ∈ R12, we have M(e1 · b12s) = M(e1 · b12a11) +M(e1 · b12a12) +M(e1 · b12a21) +M(e1 · b12a22) = M(e1 · b12a21 + e1 · b12a22). Hence e1 · b12s = e1 · b12a21 + e1 · b12a22 which implies b12(s22 − a22) = 0. Consequently R(s22 − a22) = 0. By condition (i), we have s22 = a22. The proof of (ii) is similar, since the pair (M∗−1;M−1) is also an elementary map of R×R ′. Lemma 8. The following statements are true: (i) M(a12 + b21c21) = M(a12) +M(b21c21); (ii) M(a12 + b12a22) = M(a12) +M(b12a22); (iii) M(a11 + a12a21) = M(a11) +M(a12a21); (iv) M(a21 + a22b21) = M(a21) +M(a22b21). “adm-n3” — 2019/10/20 — 9:35 — page 101 — #103 B. L. M. Ferreira 101 Proof. (i) Observing that a12 + b21c21 = e1 · (e1 + b21)(a12 + c21), we get M(a12 + b21c21) = M ( e1 · (e1 + b21)(a12 + c21) ) = M(e1) ·M ∗−1(e1 + b21)M(a12 + c21) = M(e1) · ( M∗−1(e1) +M∗−1(b21) )( M(a12) +M(c21) ) = M(e1) ·M ∗−1(e1)M(a12) +M(e1) ·M ∗−1(e1)M(c21) +M(e1) ·M ∗−1(b21)M(a12) +M(e1) ·M ∗−1(b21)M(c21) = M(e1 · e1a12) +M(e1 · e1c21) +M(e1 · b21a12) +M(e1 · b21a21) = M(a12) +M(b21a21). (ii) From Lemma 7(i) and (ii) we have M(a12 + b12a22) = M ( e1 · (e1 + b12)(a12 + a22) ) = M(e1) ·M ∗−1(e1 + b12)M(a12 + a22) = M(e1) · ( M∗−1(e1) +M∗−1(b12) )( M(a12) +M(a22) ) = M(e1) ·M ∗−1(e1)M(a12) +M(e1) ·M ∗−1(e1)M(a22) +M(e1) ·M ∗−1(b12)M(a12) +M(e1) ·M ∗−1(b12)M(a22) = M(e1 · e1a12) +M(e1 · e1a22) +M(e1 · b12a12) +M(e1 · b12a22) = M(a12) +M(b12a22). So (ii) follows. Observing that a11 + a12a21 = (a11 + a12)(e1 + a21) · e1 and a21 + a22b21 = (a21 + a22)(e1 + b21) · e1, then (iii) and (iv) can be proved similarly. Lemma 9. M(a21a12 + a22b22) = M(a21a12) +M(a22b22). Proof. We first claim that M(a21a12 · c22+a22b22 · c22) = M(a21a12 · c22)+ M(a22b22 · c22) holds for all c22 ∈ R22. Indeed, from Lemma 7(i) and (ii), we obtain M(a21a12 · c22 + a22b22 · c22) = M ( (a21 + a22)(a12 + b22) · c22 ) = M(a21 + a22)M ∗−1(a12 + b22) ·M(c22) = ( M(a21) +M(a22) )( M∗−1(a12) +M∗−1(b22) ) ·M(c22) = M(a21)M ∗−1(a12) ·M(c22) +M(a21)M ∗−1(b22) ·M(c22) +M(a22)M ∗−1(a12) ·M(c22) +M(a22)M ∗−1(b22) ·M(c22) = M(a21a12 · c22) +M(a21b22 · c22) +M(a22a12 · c22) +M(a22b22 · c22) = M(a21a12 · c22) +M(a22b22 · c22), “adm-n3” — 2019/10/20 — 9:35 — page 102 — #104 102 Additivity of elementary maps on alternative rings as desired. Now let s ∈ R such that M(s) = M(a21a12) + M(a22b22), which existence is ensured by surjectivity. Then M(e1e1 · s) = M ( e1e1 · (a21a12) ) +M ( e1e1 · (a22b22) ) = 0. Hence e1e1 · s = 0, or still s11 = s12 = 0. Similarly, we prove s21 = 0. For an arbitrary element x21 ∈ R21, it follows from Lemma 4-(iv) that M(sx21) = M(s · x21e1) = M ( (a21a12) · x21e1 ) +M ( (a22b22) · x21e1 ) = M(a21a12 · x21 + a22b22 · x21), from where we get ( s− (a21a12 + a22b22) ) x21 = 0. (1) As a next step we prove that ( s− (a21a12 + a22b22) ) x22 = 0 (2) holds for every x22 ∈ R22. First, for y21, by Lemma 4-(i) M(sx22 · y21) = M ( (a21a12)x22 · y21 ) +M ( (a22b22)x22 · y21 ) = M ( (a21a12)x22 · y21 + (a22b22)x22 · y21 ) , which implies that sx22 ·y21 = (a21a12)x22 ·y21+(a22b22)x22 ·y21. Therefore ( s− (a21a12 + a22b22) ) x22 · y21 = 0. Similarly, for y22 ∈ R22, using Lemma 4(i) M(sx22 · y22) = M ( (a21a12)x22 · y22 ) +M ( (a22b22)x22 · y22 ) = M ( (a21a12)x22 · y22 ) +M ( (a22b22)x22 · y22 ) = M ( a21(a12x22) · y22 ) +M ( (a22b22)x22 · y22 ) = M ( a21(a12x22) · y22 + (a22b22)x22 · y22 ) = M ( (a21a12)x22 · y22 + (a22b22)x22 · y22 ) yielding that sx22 · y22 = (a21a12 + a22b22)x22 · y22. Thus ( s − (a21a12 + a22b22) ) x22 · y22 = 0 and therefore we obtain that ( s− (a21a12 + a22b22) ) x22 ·R = 0. (3) Equation 3 follows from Theorem 2(i). From Equation 1 and 2, we get that ( s − (a21a12 + a22b22) ) R = 0. Hence s = a21a12 + a22b22 due to Theorem 2(i). “adm-n3” — 2019/10/20 — 9:35 — page 103 — #105 B. L. M. Ferreira 103 Taking Lemma 3 into account, we point out that Lemma 9 can still be obtained when M is replaced by M∗−1, as states the following lemma. Lemma 10. The following are true: (i) M∗−1(a12 + b12a22) = M∗−1(a12) +M∗−1(b12a22). (ii) M∗−1(a11 + a12a21) = M∗−1(a11) +M∗−1(a12a21). (iii) M∗−1(a21 + a22b21) = M∗−1(a21) +M∗−1(a22b21). (iv) M∗−1(a21a12 + a22b22) = M∗−1(a21a12) +M∗−1(a22b22). Lemma 11. M(a12 + b12) = M(a12) +M(b12). Proof. Let s ∈ R be such that M(s) = M(a12) +M(b12). Then M(e1e1 · s) = M(e1e1 · a12) + M(e1e1 · b12) = M(s) and M(s · e1e1) = M(a12 · e1e1) + M(b12 · e1e1) = 0 which implies e1e1 · s = s and s · e1e1 = 0, respectively. It follows that s21 + s22 = 0 and s11 + s21 = 0, respectively. Thus s11 = s21 = s22 = 0. For x21 ∈ R21, applying Lemma 4-(iv), M(sx21) = M(s · x21e1) = M(a12 · x21e1) +M(b12 · x21e1) = M(a12x21) +M(b12x21) = M(a12x21 + b12x21). These above equations show that sx21 = (a12 + b12)x21. Hence ( s− (a12 + b12) ) x21 = 0. (4) For all x22 ∈ R22 M∗−1(sx22) = M∗−1(e1 · sx22) = M∗−1(e1 · a12x22) +M∗−1(e1 · b12x22) = M∗−1(a12x22) +M∗−1(b12x22) = M∗−1(a12x22 + b12x22) which implies that ( s− (a12 + b12) ) x22 = 0. (5) We now want to prove that ( s − (a12 + b12) ) x12 = 0, for all x12 ∈ R12. Indeed, by Lemma 4-(vi), for y12 ∈ R12 M∗−1(y12 · sx12) = M∗−1(y12 · a12x12) +M∗−1(y12 · b12x12) = M∗−1(y12 · a12x12 + y12 · b12x12). We then get that y12 · sx12 = y12 · (a12x12 + b12x12) which implies y12 · ( s− (a12 + b12) ) x12 = 0. “adm-n3” — 2019/10/20 — 9:35 — page 104 — #106 104 Additivity of elementary maps on alternative rings For y21 ∈ R21, from Lemma 4-(vi) M∗−1(y21 · sx12) = M∗−1(y21 · a12x12) +M∗−1(y21 · b12x12) = M∗−1(y21 · a12x12 + y21 · b12x12). As a consequence y21 · sx12 = y21 · a12x12 + y21 · b12x12 which implies y21 · ( s− (a12 + b12) ) x12 = 0. Now, for y22 ∈ R22, from Lemma 4-(vi) M∗−1(y22 · sx12) = M∗−1(y22 · a12x12) +M∗−1(y22 · b12x12) = M∗−1(y22 · a12x12 + y22 · b12x12). From this, y22 · sx12 = y22 · a12x12 + y22 · b12x12 which implies y22 · ( s− (a12 + b12) ) x12 = 0. Hence R · ( s− (a12 + b12) ) x12 = 0, and therefore ( s− (a12 + b12) ) x12 = 0, (6) according to Theorem 2(ii). Moreover, from Equations 4, 5 and 6, we get that ( s−(a12+b12) ) R = 0. Due to Theorem 2(i) we have s = a12+b12. Lemma 12. M(a11 + b11) = M(a11) +M(b11). Proof. Choose s = s11 + s12 + s21 + s22 ∈ R such that M(s) = M(a11) + M(b11). Using Lemma 4-(ii) and (iv) we have M(e1e1 · s) = M(s) and M(s · e1e1) = M(s), which implies s21 + s22 = 0 and s12 + s22 = 0, respectively. Hence s12 = s21 = s22 = 0. These equations show that s = s11 and so s− (a11 + b11) ∈ R11. Next let x12 ∈ R12 arbitrarily chosen. Applying Lemma 4-(iv) we get that M(sx12) = M(s · e1x12) = M(a11 · e1x12) +M(b11 · e1x12) = M(a11 · e1x12 + b11 · e1x12) = M(a11x12 + b11x12) which yields sx12 = (a11 + b11)x12. Therefore ( s − (a11 + b11) ) R12 = 0 or still ( s − (a11 + b11) ) ·R(1 − e1) = 0. Since s − (a11 + b11) ∈ R11, it follows from Theorem 2(iii) that s = a11 + b11. Lemma 13. M is additive on e1R = R11 +R12. Proof. The proof is the same as that of Martindale III (1969, Lemma 5) and is included for the sake of completeness. Indeed, let a11, b11 ∈ R11 “adm-n3” — 2019/10/20 — 9:35 — page 105 — #107 B. L. M. Ferreira 105 and a12, b12 ∈ R12. According to Lemmas 7, 11 and 12 M ( (a11 + a12) + (b11 + b12) ) = M ( (a11 + b11) + (a12 + b12) ) = M(a11 + b11) +M(a12 + b12) = M(a11) +M(b11) +M(a12) +M(b12) = M(a11 + a12) +M(b11 + b12), as desired. Proof of Theorem 2. Suppose that a, b ∈ R and choose s ∈ R such that M(s) = M(a) + M(b). For all α ∈ Λ, M is additive on eαR due to Lemma 13. Thus, for every r ∈ R, we have M(eα · rs) = M(eα) ·M ∗−1(r)M(s) = M(eα) ·M ∗−1(r) ( M(a) +M(b) ) = M(eα) ·M ∗−1(r)M(a) +M(eα) ·M ∗−1(r)M(b) = M(eα · ra) +M(eα · rb) = M(eα · ra+ eα · rb) = M ( eα · r(a+ b) ) , and therefore eα · rs = eα · r(a + b). Hence eα ·R ( s − (a + b) ) = 0, for every α ∈ Λ. We then conclude that s = a+ b from Theorem 2(ii). This shows that M is additive on R. In order to prove the additivity of M∗, let x, y ∈ R ′. For a, b ∈ R, by using the additivity of M , we have M ( a ( M∗(x) +M∗(y) ) · b ) = M ( aM∗(x) · b ) +M ( aM∗(y) · b ) = M(a)x ·M(b) +M(a)y ·M(b) = M(a)(x+ y) ·M(b) = M ( aM∗(x+ y) · b ) . It follows that a ( M∗(x)+M∗(y)−M∗(x+y) ) ·b = 0, for all a, b ∈ R, which forces M∗(x+ y) = M∗(x) +M∗(y) according to Theorem 2, completing the proof. Corollary 1. Let R be a 2 and 3-torsion free prime alternative ring con- taining a non-trivial idempotent (R need not have an identity element), and let R′ be an arbitrary alternative ring. Then every surjective elementary map (M,M∗) of R×R ′ is additive. Proof. The result follows directly from Theorem 2 and [2, Theorem 2.2]. “adm-n3” — 2019/10/20 — 9:35 — page 106 — #108 106 Additivity of elementary maps on alternative rings Corollary 2. Let A be a prime non-degenerate alternative algebra on a field of characteristic 6= 2 containing a idempotent (A need not have an identity element), and let A′ be an arbitrary alternative algebra. Then every surjective elementary map (M,M∗) of A× A ′ is additive. Proof. The result follows directly from Theorem 2 and [1, Theorem 1]. References [1] K. I. Beidar, A. V. Mikhalev and A. M. Slinko: A criterion for non-degenerate alternative and Jordan algebras to be prime (Russian). Tr. Mosk. Mat. O.-va 50 (1987) 130-137. [2] J. C. M. Ferreira and H. Guzzo Jr: Jordan Elementary Maps on Alternative Rings. Comm. Algebra (2) 42 (2014) 779-794. [3] I. R. Hentzel, E. Kleinfeld and H. F. Smith: Alternative Rings with Idempotent. J. Algebra 64 (1980) 325-335. [4] P. Li and F. Lu: Additivity of Elementary Maps on Rings. Comm. Algebra 32 (2004) 3725-3737. [5] W. S. Martindale III: When are multiplicative mappings additive? Proc. Amer. Math. Soc. 21 (1969) 695-698. [6] M. Slater: Prime alternative rings I. J. Algebra 15 (1970) 229-243. [7] K. A. Zhevlakov, A. M. Slin’ko, I. P. Shestakov and A. I. Shirshov: Rings that are nearly associative. Inst. Math. Acad. Sci. of the U.S.S.R., Siberian Branch Novosibirsk, U.S.S.R., Academic Press, New York (1982). Contact information Bruno Leonardo Macedo Ferreira Universidade Tecnológica Federal do Paraná, Avenida Professora Laura Pacheco Bastos, 800, 85053-510, Guarapuava, Brazil E-Mail(s): brunoferreira@utfpr.edu.br Received by the editors: 20.01.2018 and in final form 25.01.2018.